im new with C can someone help me with that?

[Liam mallka]

What the output of the next plan and explain why this is the output.

[Sauron]

Why don't you just run it and find out? We're not here to do your homework.

[Teddy07]

You need to initlize the variable a with an integer, which means add a value. a as it stands is uninitilized and has no value. You can therefore not use it.

 

Also please add return 0 at the end of every c main to end the program. There are other ways but this is best practice. It just shows that wenn your program ends with 0, than it ran successfully.

[Teddy07]

3 minutes ago, Sakuriru said:

just read whatever eight bits happen to be there, which could be anything

I assume C tries to interpret the unitilized bit value at the location as an integer? Because a string value would be an error

[mariushm]

int a;   defines a variable called a , but doesn't assign any value to it.   Some C compilers will auto initialize it with value 0, others won't, so when reading the value you'll simply read whatever was in computer ram where the a variable was put.

 

printf prints variables according to the pattern you give it ... %d means a decimal number,  so it will print whatever is stored in the 4 or 8 bytes the variable a reserved in memory (int size depends on compiler and architecture, could be 2 bytes on 16 bit microcontrollers, but usually it's 32 bits or 4 bytes)

 

the function doesn't return anything, and doesn't have to, because you used the void keyword in front of the function name.

[shadow_ray]

3 hours ago, Teddy07 said:

I assume C tries to interpret the unitilized bit value at the location as an integer?

Yep

3 hours ago, Teddy07 said:

Because a string value would be an error

I don't thinks so. A string in C is just a pointer.

#include <stdio.h>

int main(){    
  int a = 0x6c6c6568;
  int b = 0x6f77206f;
  int c = 0x00646c72;
  printf("\n%s", (char*)&a);

  int data[] = {0x6c6c6568, 0x6f77206f, 0x00646c72};
  printf("\n%s", (char*)&data);
  
  printf("\n%s", "hello world");
  
  return 0;
}

 

 

[Teddy07]

23 minutes ago, shadow_ray said:

Yep

I don't thinks so. A string in C is just a pointer.

#include <stdio.h>

int main(){    
  int a = 0x6c6c6568;
  int b = 0x6f77206f;
  int c = 0x00646c72;
  printf("\n%s", (char*)&a);

  int data[] = {0x6c6c6568, 0x6f77206f, 0x00646c72};
  printf("\n%s", (char*)&data);
  
  printf("\n%s", "hello world");
  
  return 0;
}

 

 

thanks man. Always good to keep learning. I was too lazy to test