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is my ram running slower?

Blackhole890
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Go to solution Solved by -rascal-,
8 minutes ago, Blackhole890 said:

the memory: Kingston ValueRAM DDR3 1333 PC3-10600 4GB CL9d60f20ebb3.png

 

Also the "SPD" tab doesn't show WHAT speed your RAM is currently running at; it just shows the frequency and timings programmed into it.

 

What you should be looking at is the "Memory" tab.

 

For DDR3-1333 MHz, it should be showing up as ~667 MHz.

 

DDR = Double Data Rate.

The effective frequency is 1333 MHz.

The actual frequency is ~666.66 MHz.

 

The RAM operates on both the rising-edge and failing-edge of a clock cycle.

 

401px-SDR_DDR_QDR.svg.png

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8 minutes ago, Blackhole890 said:

the memory: Kingston ValueRAM DDR3 1333 PC3-10600 4GB CL9d60f20ebb3.png

 

Also the "SPD" tab doesn't show WHAT speed your RAM is currently running at; it just shows the frequency and timings programmed into it.

 

What you should be looking at is the "Memory" tab.

 

For DDR3-1333 MHz, it should be showing up as ~667 MHz.

 

DDR = Double Data Rate.

The effective frequency is 1333 MHz.

The actual frequency is ~666.66 MHz.

 

The RAM operates on both the rising-edge and failing-edge of a clock cycle.

 

401px-SDR_DDR_QDR.svg.png

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Posted

666*2 = 1333

It is running at the correct speed.

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19 minutes ago, -rascal- said:

 

Also the "SPD" tab doesn't show WHAT speed your RAM is currently running at; it just shows the frequency and timings programmed into it.

 

What you should be looking at is the "Memory" tab.

 

For DDR3-1333 MHz, it should be showing up as ~667 MHz.

 

DDR = Double Data Rate.

The effective frequency is 1333 MHz.

The actual frequency is ~666.66 MHz.

 

The RAM operates on both the rising-edge and failing-edge of a clock cycle.

 

401px-SDR_DDR_QDR.svg.png

 

12 minutes ago, Enderman said:

666*2 = 1333

It is running at the correct speed.

so if the ram runs as effective 2133, the actual would be 1066?

Remember to quote me (or someone else), otherwise we won't going to recieve your answers...

 

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1 minute ago, Blackhole890 said:

 

so if the ram runs as effective 2133, the actual would be 1066?

Yes

 

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