radiators size question

[EcDarkSky]

Hi guys,

I would like to know if a 240mm radiator (push and pull) will support a r9 290 not overclocked and a I5 6600K a bit overlcocked around 4 to 4.4 ghz

Thanks for answer

[Belgarathian]

That will be fine. 

[pagani123]

i would add another 120mm atleast to keep everything cool 

[W-L]

Hi guys,

I would like to know if a 240mm radiator (push and pull) will support a r9 290 not overclocked and a I5 6600K a bit overlcocked around 4 to 4.4 ghz

Thanks for answer

 

You would be at the bare minimum of 120mm of rad space per component, I would recommend at least a total of 360mm of rad space for that kind of setup.

[0ld_Chicken]

Hi guys,

I would like to know if a 240mm radiator (push and pull) will support a r9 290 not overclocked and a I5 6600K a bit overlcocked around 4 to 4.4 ghz

Thanks for answer

as long as its not a "slim" with low fpi then it should work, but it wont stay the coolest and will require more airflow to keep cool.  adding more rad space would help keep things cool and quiet (if that is your goal)

[stealth80]

I wouldn't talking from experience. I had a 3770K and a Sapphire Vapor 280X on a 240mm (60mm) in push pull and the temps weren't great, it cause my eventual switch to my current build.

[anthonyc813]

You would be at the bare minimum of 120mm of rad space per component, I would recommend at least a total of 360mm of rad space for that kind of setup.

Going by what you said, so a cpu and two cards would mean you need a 480?

[W-L]

Going by what you said, so a cpu and two cards would mean you need a 480?

 

A 360mm would work if everything was at stock but if you wanted to do overclocking a 480mm or slightly more wouldn't hurt if you wanted silent cooling.

[anthonyc813]

A 360mm would work if everything was at stock but if you wanted to do overclocking a 480mm or slightly more wouldn't hurt if you wanted silent cooling.

cool thanks for the reply. seeing a lot of pics with one 360 and another 240 or 120 somewhere wlse in the case

[stealth80]

The more rads you have the more surface area you have to ditch heat and the more fans. Basically means you can run the fans at lower speeds (less noise) to maintain same temps as less rads

[BrightCandle]

It always surprises me when someone asks a question like this and no one actually responds with how this all works. You need to dissipate the heat that is put into the loop, and that is equal to the TDP of the components you are cooling. A 6600K stock is 77W, a bit overclocked lets say 100W but it could be up to 150W. The R9 290 is a 300W GPU. So combined you are putting 300+150W into the water at most or your little overclock 300W + 100W.

 

Given that we need to remove all that heat. Due to the way thermal transfer works heat flows faster as the difference in temperature gets higher, so your loop will more efficiently transfer the warmer the water gets, but that will also however make the ambient water temperature that cools the components higher. So typically we aim for at least +10C delta on the water, ideally less than that otherwise air cooling will typically outperform. We also typically use quiet fans on watercooling as most people doing it don't want the noise. So given that there are two numbers to know:

 

A thin 120mm radiator and a 800rpm (decent) fan can dissipate 90W to a 10C delta.

A thick 120mm radiator and a 800rom (decent) fan can dissipate 120W to a 10C delta.

 

Radiators do differ but its a close enough rule of thumb to size loops. The numbers I use are based on the best thin and thick radiators you could get in about 2008, which is actually still the best they can do.

 

So 400W of heat from your components divided by say a thick radiators 120W is 3.3, so a 480 radiator. Its no different for the maximum overclock.

 

Now a lot of people don't assume maximum power draw when they design water loops, I personally think that is a bad idea because these TDPs are absolutely possible and you will have issues if you can't cool it all but its possible to skimp if you know the impact. Your standard TDP for the R9 290 is 250W and maybe you'll only pull 70W out of the CPU as the grand majority of games don't run across all the cores so you can potentially get away with just 320W, which is only a thick 360mm radiator.

 

The other way to reduce radiator slots is to up the fan speeds and make the loop louder. By the time you get to 1500rpm you have more like 120W and 160W dissipation so that can make quite a big difference.

 

This is how water cooling works, 120mm per component is obviously wrong, 360mm is clearly underpowered for your loops actual TDP and whatever else all these wrong people suggested.

[QBtech]

--snip--

This besides the fact that 120(x+1) where x is amount of opponents is a good rule of thumb for the BARE minimum to get SOMEWHAT DECENT temps on a SLIGHT TO NO overclock.

It is a rule of thumb, not science. A 240 will keep the mentioned components under the thermal threshold on stock.

[B NEGATIVE]

It always surprises me when someone asks a question like this and no one actually responds with how this all works. You need to dissipate the heat that is put into the loop, and that is equal to the TDP of the components you are cooling. A 6600K stock is 77W, a bit overclocked lets say 100W but it could be up to 150W. The R9 290 is a 300W GPU. So combined you are putting 300+150W into the water at most or your little overclock 300W + 100W.

 

Given that we need to remove all that heat. Due to the way thermal transfer works heat flows faster as the difference in temperature gets higher, so your loop will more efficiently transfer the warmer the water gets, but that will also however make the ambient water temperature that cools the components higher. So typically we aim for at least +10C delta on the water, ideally less than that otherwise air cooling will typically outperform. We also typically use quiet fans on watercooling as most people doing it don't want the noise. So given that there are two numbers to know:

 

A thin 120mm radiator and a 800rpm (decent) fan can dissipate 90W to a 10C delta.

A thick 120mm radiator and a 800rom (decent) fan can dissipate 120W to a 10C delta.

 

Radiators do differ but its a close enough rule of thumb to size loops. The numbers I use are based on the best thin and thick radiators you could get in about 2008, which is actually still the best they can do.

 

So 400W of heat from your components divided by say a thick radiators 120W is 3.3, so a 480 radiator. Its no different for the maximum overclock.

 

Now a lot of people don't assume maximum power draw when they design water loops, I personally think that is a bad idea because these TDPs are absolutely possible and you will have issues if you can't cool it all but its possible to skimp if you know the impact. Your standard TDP for the R9 290 is 250W and maybe you'll only pull 70W out of the CPU as the grand majority of games don't run across all the cores so you can potentially get away with just 320W, which is only a thick 360mm radiator.

 

The other way to reduce radiator slots is to up the fan speeds and make the loop louder. By the time you get to 1500rpm you have more like 120W and 160W dissipation so that can make quite a big difference.

 

This is how water cooling works, 120mm per component is obviously wrong, 360mm is clearly underpowered for your loops actual TDP and whatever else all these wrong people suggested.

 

 

You are so very wrong,mainly because of your assumption that a 10c delta is desired or needed.

 

So this is an EK Vulture with a pair of 290x's and a 4.3 oc on the x99 6 core on a less than ideal fully parallel loop.....with a skinny PE 360,fans at 1200 Rpm

 

 

And core temps from a 1h OCCT run.

 

Add the GPU's in there gaming and temps dont exceed 45c on the core for those,the last pic shows the temps after a combined run.

 

When the delta increases so does the efficiency of the rads,a single 120 can dissipate 250w easily,the higher the water temp then the efficiency climbs in relation to the ambient.

 

Also worth pointing out is that TDP is a meaningless value,TDP to Intel is total draw in a throttled scenario,a worst case thermal scenario,AMD use it for total load package draw. The same applies to GPU's.

[stealth80]

Basic rule been 120 per component + 120mm, which in case equates to 360mm for 1 cpu and 1 gpu, you wrote a massive thread saying everyone is wrong but came to the same conclusion

 

The above should work for gaming at low to medium fan speeds, if the pc does create max power draw there is still plenty of cooling potential within the fans

[B NEGATIVE]

Basic rule been 120 per component + 120mm, which in case equates to 360mm for 1 cpu and 1 gpu, you wrote a massive thread saying everyone is wrong but came to the same conclusion

 

The above should work for gaming at low to medium fan speeds, if the pc does create max power draw there is still plenty of cooling potential within the fans

 

 

Correct.