pyhton get character from list

[Wictorian]

So I have a list containing 20 lists each with 20 characters.

columnLists.append(rowLists[c][0])

when I write this I expect to get a character. Instead I get a whole list. How can I only get a character

 

[straight_stewie]

1 minute ago, Wictorian said:

when I write this I expect to get a character. Instead I get a whole list. How can I only get a character

Can we see the code where you create the list of lists of characters?

[Wictorian]

5 minutes ago, straight_stewie said:

Can we see the code where you create the list of lists of characters?

a = """
08 02 22 97 38 15 00 40 00 75 04 05 07 78 52 12 50 77 91 08
49 49 99 40 17 81 18 57 60 87 17 40 98 43 69 48 04 56 62 00
81 49 31 73 55 79 14 29 93 71 40 67 53 88 30 03 49 13 36 65
52 70 95 23 04 60 11 42 69 24 68 56 01 32 56 71 37 02 36 91
22 31 16 71 51 67 63 89 41 92 36 54 22 40 40 28 66 33 13 80
24 47 32 60 99 03 45 02 44 75 33 53 78 36 84 20 35 17 12 50
32 98 81 28 64 23 67 10 26 38 40 67 59 54 70 66 18 38 64 70
67 26 20 68 02 62 12 20 95 63 94 39 63 08 40 91 66 49 94 21
24 55 58 05 66 73 99 26 97 17 78 78 96 83 14 88 34 89 63 72
21 36 23 09 75 00 76 44 20 45 35 14 00 61 33 97 34 31 33 95
78 17 53 28 22 75 31 67 15 94 03 80 04 62 16 14 09 53 56 92
16 39 05 42 96 35 31 47 55 58 88 24 00 17 54 24 36 29 85 57
86 56 00 48 35 71 89 07 05 44 44 37 44 60 21 58 51 54 17 58
19 80 81 68 05 94 47 69 28 73 92 13 86 52 17 77 04 89 55 40
04 52 08 83 97 35 99 16 07 97 57 32 16 26 26 79 33 27 98 66
88 36 68 87 57 62 20 72 03 46 33 67 46 55 12 32 63 93 53 69
04 42 16 73 38 25 39 11 24 94 72 18 08 46 29 32 40 62 76 36
20 69 36 41 72 30 23 88 34 62 99 69 82 67 59 85 74 04 36 16
20 73 35 29 78 31 90 01 74 31 49 71 48 86 81 16 23 57 05 54
01 70 54 71 83 51 54 69 16 92 33 48 61 43 52 01 89 19 67 48"""

rowLists = []
rows = a.replace("\r", "").split("\n")
for row in rows:
    if(not len(row)):
        continue
    rowLists.append(row.split())
print(rowLists)

 

[AndreiArgeanu]

43 minutes ago, Wictorian said:

So I have a list containing 20 lists each with 20 characters.

columnLists.append(rowLists[c][0])

when I write this I expect to get a character. Instead I get a whole list. How can I only get a character

 

Is that inside a loop? Because running that on it's own (also replacing c with an integer) it only gives out 1 object from the list.

[Wictorian]

8 minutes ago, AndreiArgeanu said:

Is that inside a loop? Because running that on it's own (also replacing c with an integer) it only gives out 1 object from the list.

yeah its in a loop

[AndreiArgeanu]

2 minutes ago, Wictorian said:

yeah its in a loop

Then most likely there's something wrong in your loop, perhaps it gathers way more characters then it's supposed to.

[Wictorian]

2 minutes ago, AndreiArgeanu said:

Then most likely there's something wrong in your loop, perhaps it gathers way more characters then it's supposed to.

for d in range(19):
    for e in range(19):
        columnLists[d].append(rowLists[e][d])

I am not sure if its right but this is my loop.

[AndreiArgeanu]

12 minutes ago, Wictorian said:

for d in range(19):
    for e in range(19):
        columnLists[d].append(rowLists[e][d])

I am not sure if its right but this is my loop.

That's because you're running the for loop below 19 times therefore you get 361 items in your list. Also the [d] that follows columLists gives out an index error. So the for loop for e in range(19): is ran 19 times. That's why you're getting so many items.

 

[straight_stewie]

I'm confused about your problem. This code gives me what I would expect, which is a list of lists of strings and the first string in the first list:

a = """
08 02 22 97 38 15 00 40 00 75 04 05 07 78 52 12 50 77 91 08
49 49 99 40 17 81 18 57 60 87 17 40 98 43 69 48 04 56 62 00
81 49 31 73 55 79 14 29 93 71 40 67 53 88 30 03 49 13 36 65
52 70 95 23 04 60 11 42 69 24 68 56 01 32 56 71 37 02 36 91
22 31 16 71 51 67 63 89 41 92 36 54 22 40 40 28 66 33 13 80
24 47 32 60 99 03 45 02 44 75 33 53 78 36 84 20 35 17 12 50
32 98 81 28 64 23 67 10 26 38 40 67 59 54 70 66 18 38 64 70
67 26 20 68 02 62 12 20 95 63 94 39 63 08 40 91 66 49 94 21
24 55 58 05 66 73 99 26 97 17 78 78 96 83 14 88 34 89 63 72
21 36 23 09 75 00 76 44 20 45 35 14 00 61 33 97 34 31 33 95
78 17 53 28 22 75 31 67 15 94 03 80 04 62 16 14 09 53 56 92
16 39 05 42 96 35 31 47 55 58 88 24 00 17 54 24 36 29 85 57
86 56 00 48 35 71 89 07 05 44 44 37 44 60 21 58 51 54 17 58
19 80 81 68 05 94 47 69 28 73 92 13 86 52 17 77 04 89 55 40
04 52 08 83 97 35 99 16 07 97 57 32 16 26 26 79 33 27 98 66
88 36 68 87 57 62 20 72 03 46 33 67 46 55 12 32 63 93 53 69
04 42 16 73 38 25 39 11 24 94 72 18 08 46 29 32 40 62 76 36
20 69 36 41 72 30 23 88 34 62 99 69 82 67 59 85 74 04 36 16
20 73 35 29 78 31 90 01 74 31 49 71 48 86 81 16 23 57 05 54
01 70 54 71 83 51 54 69 16 92 33 48 61 43 52 01 89 19 67 48"""

rowLists = []
rows = a.replace("\r", "").split("\n")
for row in rows:
    if(not len(row)):
        continue
    rowLists.append(row.split())
print(rowLists)
print()
print(rowLists[0][0])

 

 

Is the problem possibly that you are expecting a single character but are instead getting a string? For example, rowLists[0][0] gives me "08" rather than '0'.

[Wictorian]

5 hours ago, straight_stewie said:

I'm confused about your problem. This code gives me what I would expect, which is a list of lists of strings and the first string in the first list:

a = """
08 02 22 97 38 15 00 40 00 75 04 05 07 78 52 12 50 77 91 08
49 49 99 40 17 81 18 57 60 87 17 40 98 43 69 48 04 56 62 00
81 49 31 73 55 79 14 29 93 71 40 67 53 88 30 03 49 13 36 65
52 70 95 23 04 60 11 42 69 24 68 56 01 32 56 71 37 02 36 91
22 31 16 71 51 67 63 89 41 92 36 54 22 40 40 28 66 33 13 80
24 47 32 60 99 03 45 02 44 75 33 53 78 36 84 20 35 17 12 50
32 98 81 28 64 23 67 10 26 38 40 67 59 54 70 66 18 38 64 70
67 26 20 68 02 62 12 20 95 63 94 39 63 08 40 91 66 49 94 21
24 55 58 05 66 73 99 26 97 17 78 78 96 83 14 88 34 89 63 72
21 36 23 09 75 00 76 44 20 45 35 14 00 61 33 97 34 31 33 95
78 17 53 28 22 75 31 67 15 94 03 80 04 62 16 14 09 53 56 92
16 39 05 42 96 35 31 47 55 58 88 24 00 17 54 24 36 29 85 57
86 56 00 48 35 71 89 07 05 44 44 37 44 60 21 58 51 54 17 58
19 80 81 68 05 94 47 69 28 73 92 13 86 52 17 77 04 89 55 40
04 52 08 83 97 35 99 16 07 97 57 32 16 26 26 79 33 27 98 66
88 36 68 87 57 62 20 72 03 46 33 67 46 55 12 32 63 93 53 69
04 42 16 73 38 25 39 11 24 94 72 18 08 46 29 32 40 62 76 36
20 69 36 41 72 30 23 88 34 62 99 69 82 67 59 85 74 04 36 16
20 73 35 29 78 31 90 01 74 31 49 71 48 86 81 16 23 57 05 54
01 70 54 71 83 51 54 69 16 92 33 48 61 43 52 01 89 19 67 48"""

rowLists = []
rows = a.replace("\r", "").split("\n")
for row in rows:
    if(not len(row)):
        continue
    rowLists.append(row.split())
print(rowLists)
print()
print(rowLists[0][0])

 

 

Is the problem possibly that you are expecting a single character but are instead getting a string? For example, rowLists[0][0] gives me "08" rather than '0'.

Yeah I was confused about it too.

No I expect to get a two digit number but I think I solved it anyways.

 

edit : Ohhh,  instead of [c][0] ı must have put [0][c}

Edited January 6, 2021 by Wictorian