Surprising maths.

[Nineshadow]

I got bored today and I made this :

 -((sin²(45°)+cos²(45°))*(-1))^½ > u^(-1) * u + (-((½ + u)² + ¾)) + ((u-1)²-1)

                                     -(-1)^½ > 1 + (-(¼ + u² + u + ¾)) + ( u² + 1 - 2u - 1)

                                - sqrt(-1) > 1 - 1 - u - u² + u² -2u

                                            -i > -3u

                                i<3u 

 

 

Them typos.

[nsyedhasan]

Lik if you cri evrytim.

[needmorewood]

Cute
gonna steal that from you
 

[Sarcasm]

Using degrees instead of radians in an equation. 0/10 wow really bad.

[TechSage]

my brain hurts.

[ivhyn]

Give me some time to reenact your maths skills

[M-ursu]

[Nineshadow]

Using degrees instead of radians in an equation. 0/10 wow really bad.

I never liked radians.

[Sarcasm]

I never liked radians.

 

(45° to radians is pi/2)

 

Degrees are an abstract value we just happen to assign to an angle. Pi (and tau) is an actual ratio of an angle's radius to its arc length. Anything in a higher math will use radians.

[Raboo]

Over load

[ivhyn]

I never liked radians.

(45° to radians is pi/2)

45 degrees is pi/4, pi is 180 degrees

[Nineshadow]

Degrees are an abstract value we just happen to assign to an angle. Pi (and tau) is an actual ratio of an angle's radius to its arc length. Anything in a higher math will use radians.

But I'm not into that high math yet D:

[AlexGoesHigh]

this is the reason i dint make it to the uni x.x

[Canoas]

Sorry, but that's wrong.

(-((sin²(45°)+cos²(45°)^½) = -1.207

 

and even if it was equal to (-( 1^½))..

(-( 1^½)) = -sqrt(1) = -3/2

 

 

Now, on the right side,

The first line is wrong

u^(-1) * u * (-((½ + u)² + ¾)) + ((u-1)²-1) =

= (-((½ + u)² + ¾)) + ( u² + 1 - 2u - 1) =

= -(¼ + u + u²) - ¾ + ( u² + 1 - 2u - 1) =

= -1 - u - u² + u² - 2u =

= -1 -3u

 

The second line is also wrong

1 + ( ¼ + u² + u + ¾)) + ( u² + 1 - 2u - 1) =

= 1 + (1 + u^2 + u) + (u^2 - 2u) =

= 2 - u + 2u^2

 

 

So basically you're making mistakes upon mistakes.

The first line's results would be:

(-((sin²(45°)+cos²(45°)^½) > u^(-1) * u * (-((½ + u)² + ¾)) + ((u-1)²-1)

-1.207 > -1 -3u

-0.207 > -3u

0.207 < 3u

 

According to the second line, which is not the same thing as the first:

(-( 1^½)) > 1 + ( ¼ + u² + u + ¾)) + ( u² + 1 - 2u - 1)

-3/2 > 2 - u + 2u²

2u > 4u² + 7   <= this is impossible btw, there are no solutions

 

Everything is wrong, sorry.

[Art Vandelay]

Degrees are an abstract value we just happen to assign to an angle. Pi (and tau) is an actual ratio of an angle's radius to its arc length. Anything in a higher math will use radians.

If you consider first year physics higher math lol.

 

For some reason my circuits prof likes to use degrees though when writing complex number equations, though. It's really weird.

[Nineshadow]

Sorry, but that's wrong.

(-((sin²(45°)+cos²(45°)^½) = -1.207

 

and even if it was equal to (-( 1^½))..

(-( 1^½)) = -sqrt(1) = -3/2

 

 

Now, on the right side,

The first line is wrong

u^(-1) * u * (-((½ + u)² + ¾)) + ((u-1)²-1) =

= (-((½ + u)² + ¾)) + ( u² + 1 - 2u - 1) =

= -(¼ + u + u²) - ¾ + ( u² + 1 - 2u - 1) =

= -1 - u - u² + u² - 2u =

= -1 -3u

 

The second line is also wrong

1 + ( ¼ + u² + u + ¾)) + ( u² + 1 - 2u - 1) =

= 1 + (1 + u^2 + u) + (u^2 - 2u) =

= 2 - u + 2u^2

 

 

So basically you're making mistakes upon mistakes.

The first line's results would be:

(-((sin²(45°)+cos²(45°)^½) > u^(-1) * u * (-((½ + u)² + ¾)) + ((u-1)²-1)

-1.207 > -1 -3u

-0.207 > -3u

0.207 < 3u

 

According to the second line, which is not the same thing as the first:

(-( 1^½)) > 1 + ( ¼ + u² + u + ¾)) + ( u² + 1 - 2u - 1)

-3/2 > 2 - u + 2u²

2u > 4u² + 7   <= this is impossible btw, there are no solutions

 

Everything is wrong, sorry.

My bad.

Should've been

 -((sin²(45°)+cos²(45°))*(-1))^½

 

sin²(x)+cos²(x) is 1;

Then, I forgot to multiply that by -1,so we can get -1;

-(-1)^½ is -sqrt(-1);

-sqrt(-1)=-i;

 

 

 

 

 

u^(-1) * u * (-((½ + u)² + ¾)) + ((u-1)²-1)

 

Should have been

 

 

 

u^(-1) * u + (-((½ + u)² + ¾)) + ((u-1)²-1)

Then, we'll have

1 + (-(¼ + u² + 2*½u + ¾)) + (u² + 1 - 2 u - 1) =

= 1 + (-(1 + u² + u)) + u² -2u =

= 1 - 1 - u² - u + u² - 2u=

=-3u

 

It was hard to type this at 3AM without any mistakes D:

Thanks for showing me what was wrong.

[Canoas]

If you consider first year physics higher math lol.

 

For some reason my circuits prof likes to use degrees though when writing complex number equations, though. It's really weird.

In all my calculus, physics, circuits, signals and systems classes I've always used radians. The only time I remember degrees being the norm was in optics because it's easier to work with 47º than 47*pi/180

[cacra]

Radians are a purer form of degrees just as maths is a purer form of physics.

[Biased Opinion]

I really hate the use of "u" rather that "x"