Python, Making it tidy?

[mattonfire]

Hello, is there any way I can make this more line economical?

http://hastebin.com/bekizokale.coffee

(Python 3.3.5).

[AnonymousGuy]

You have no checks if they enter something unexpected.

 

I would do something like have an input file that I feed all my choices into and then a for loop to print them out.  Might not save line space (which doesn't really matter IMO) but would make it so you can reconfigure it easier without changing code.

 

if again in ['y', 'Y', 'yes', 'Yes', 'YES', 'ye', 'Ye', 'YE']:

 

Just do a regular expression looking for "^y" case insensitive.  Or if you want to save execution cycles (maybe) just check the first character of their response for y or Y.

[mattonfire]

You have no checks if they enter something unexpected.

 

I would do something like have an input file that I feed all my choices into and then a for loop to print them out.  Might not save line space (which doesn't really matter IMO) but would make it so you can reconfigure it easier without changing code.

 

if again in ['y', 'Y', 'yes', 'Yes', 'YES', 'ye', 'Ye', 'YE']:

 

Just do a regular expression looking for "^y" case insensitive.  Or if you want to save execution cycles (maybe) just check the first character of their response for y or Y.

Still new, is there a way you can show me by editing my hastebin? I understand the code in visual form. Still getting used to the words.

 

You see any way of making this shorter?

    if tutor in ['A', 'a']:

        group=("10 Fraser")

    if tutor in ['B', 'b']:

        group=("10 Nisdale")

    if tutor in ['C', 'c']:

        group=("10 Douglas")

    if tutor in ['D', 'd']:

        group=("10 Darby")

    if tutor in ['E', 'e']:

        group=("10 Tudor")

    if tutor in ['F', 'f']:

        group=("10 Lincoln")

[AnonymousGuy]

 

Still new, is there a way you can show me by editing my hastebin? I understand the code in visual form. Still getting used to the words.

 

You see any way of making this shorter?

    if tutor in ['A', 'a']:

        group=("10 Fraser")

    if tutor in ['B', 'b']:

        group=("10 Nisdale")

    if tutor in ['C', 'c']:

        group=("10 Douglas")

    if tutor in ['D', 'd']:

        group=("10 Darby")

    if tutor in ['E', 'e']:

        group=("10 Tudor")

    if tutor in ['F', 'f']:

        group=("10 Lincoln")

 

Yes.  I'm working on it now.  I don't know Python so I'm learning the syntax for what I want to do.  Once you know one language (in my case Perl in addition to several others), you know them all.

[mattonfire]

Yes.  I'm working on it now.  I don't know Python so I'm learning the syntax for what I want to do.  Once you know one language (in my case Perl in addition to several others), you know them all.

Oh right, that's quite interesting. 

Thanks by the way.

[AnonymousGuy]

Oh right, that's quite interesting. 

Thanks by the way.

http://hastebin.com/ikacunazos.tex

 

Might not be working fully and I don't have any exception handling / default input if the for loop exits without a match.  Should give you an idea though of what's up.  Sometimes I swear exception handling takes up more codespace than the actual function you want to implement in the first place.

[mattonfire]

http://hastebin.com/ikacunazos.tex

 

Might not be working fully and I don't have any exception handling / default input if the for loop exits without a match.  Should give you an idea though of what's up.  Sometimes I swear exception handling takes up more codespace than the actual function you want to implement in the first place.

Alrighty I will have a look, even if it doesn't work. Thanks for your time.