help Java Rock Paper Scissors Help

[kurtstir]

Hello,

I was wondering if somebody could help me with this Java, i'm still learning, only started about a week ago, and I just cannot figure out what to do from here. I need the user to be able to enter in a win number and then have that many games be played to win. I also need to be able to have a constant score board with Computer Wins, Human Wins, and Ties. 

 

import javax.swing.JOptionPane;
import java.util.Random;

public class RPS2
{
    public static void main(String args[])
    {Random R = new Random();
    		int myNum = R.nextInt(3)+1;
    			
    		//	System.out.println(52 6f 73 65);
    		String numInputA = JOptionPane.showInputDialog("How many wins will end the tournament?");
    			double numInput2 = Double.parseDouble(numInputA);
    		String numInput = JOptionPane.showInputDialog("Which would you like?:\n\n1.Rock\n2.Paper\n3.Scissors");
    			double numInput1 = Double.parseDouble(numInput);
    			
    		if (myNum==1) {
    			JOptionPane.showMessageDialog(null,"I Pick Rock");
    		}
    			else
    		if (myNum==2) {
    			JOptionPane.showMessageDialog(null,"I Pick Paper");
    		}
    			else
    		if (myNum==3) {
    			JOptionPane.showMessageDialog(null,"I pick Scissors");
    		}
    		//
    		if (numInput1==1 && myNum==3) {
    			JOptionPane.showMessageDialog(null,"You Won\n\n1.Wins\n2. Computer\n3. Humans\n4. Ties");
    		}
    		else
    		if (numInput1==2 && myNum==2) {
    			JOptionPane.showMessageDialog(null,"You Lose\n\n1.Wins\n2. Computer\n3. Humans\n4. Ties");
    		}
    		else
    		if (numInput1==3 && myNum==1) {
    			JOptionPane.showMessageDialog(null,"You Tied\n\n1.Wins\n2. Computer\n3. Humans\n4. Ties");
    		}
    		//
    		if (numInput1==2 && myNum==1) {
    			JOptionPane.showMessageDialog(null,"You Won\n\n1.Wins\n2. Computer\n3. Humans\n4. Ties");
    		}
    		else
    		if (numInput1==2 && myNum==3) {
    			JOptionPane.showMessageDialog(null,"You Lose\n\n1.Wins\n2. Computer\n3. Humans\n4. Ties");
    		}
    		else
    		if (numInput1==2 && myNum==2) {
    			JOptionPane.showMessageDialog(null,"You Tied\n\n1.Wins\n2. Computer\n3. Humans\n4. Ties");
    				//
    		if (numInput1==3 && myNum==2) {
    			JOptionPane.showMessageDialog(null,"You Won\n\n1.Wins\n2. Computer\n3. Humans\n4. Ties");
    		}
    		else
    		if (numInput1==3 && myNum==1) {
    			JOptionPane.showMessageDialog(null,"You Lose\n\n1.Wins\n2. Computer\n3. Humans\n4. Ties");
    		}
    		else
    		if (numInput1==3 && myNum==3) {
    			JOptionPane.showMessageDialog(null,"You Tied\n\n1.Wins\n2. Computer\n3. Humans\n4. Ties");
    		}
    		
    }
    
    
}

}

 

[LtStaffel]

10 minutes ago, kurtstir said:

Hello,

I was wondering if somebody could help me with this Java, i'm still learning, only started about a week ago, and I just cannot figure out what to do from here. I need the user to be able to enter in a win number and then have that many games be played to win. I also need to be able to have a constant score board with Computer Wins, Human Wins, and Ties. 

-snip-

 

Grab input and run the entire game in a for loop to start at 1 and increment every time a game is played until the your loop counter variable is greater than the integer input.

 

Poke me on PM and I might be able to help actually write that and a bit more later, those if/else's are untidy and a switch statement would be much cleaner if it's possible.

 

Also, that's Java, not JavaScript... Maybe I won't be able to help as much. I know you'll need to import Scanner or something like it to get input.

[jj9987]

Store the required winnings, winnings, loses, ties into variables, for example int. Then you can easily access them. If you need to have it persistent, save it to a file and load when app is opened.

 

As for the UI, it looks weird/incomplete, but I have not used that myself and may be wrong.

As @LtStaffel said, you need to use Scanner if you need to get the input from console. If you are using a GUI, then it depends on the framework you use.

 

And yea, as said above, this is Java, not JavaScript. There's a very big difference.

[vorticalbox]

@kurtstir lets sort your logic a little bit, make it neater.

 

#1 = rock
#2 = paper
#3 = scissors 

if mynum == comp then draw

else if mynum = 1
	if comp = 3 then you win
	else you lose
else if mynum = 2
	if comp = 1 then you win
	else you lose
else if mynum = 3
	if comp = 2 then you win
	else you lose

here is a version in python for you to look over, different syntax but logic is the same.

 

from random import randint
#1 rock
#2 paper
#3 scissors

wins= 0
lose = 0
draw = 0

games = int(input("Enter number of games to play"))
for i in range(games):
  myNum = randint(1,3)
  comNum = randint(1,3)
  if(myNum == comNum):
    print("You drew")
    draw += 1
  elif(myNum == 1):
    if(comNum == 3):
      print("You win")
      wins += 1
    else:
      print("You lose")
      lose += 1
  elif(myNum == 2):
    if(comNum == 1):
      print("You win")
      wins +=1
    else:
      print("You lose")
      lose += 1
  elif(myNum == 3):
    if(comNum == 2):
      print("You win")
      wins += 2
    else:
      print("You lose")
      lose += 1
  #end of loop
print("You won {} lost {} and drew {}".format(wins, lose, draw))

Output

Enter number of games to play 5
You win
You lose
You win
You drew
You lose
You won 3 lost 2 and drew 1