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8=(x)+(x+2)+(x+4)+(x+6) 

 

Just solve for x.

 

x will be -1 and then the x+2 will give you the 1, the x+4 will give you the 3 and the x+6 will give you the 5.

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i dont get it

how did you get thoes numbers

I edited my post, "The numbers come one after another, and they all add up to 8." 

The integer 5 comes after the integer 3, 3 comes after 1, 1 comes after -1, assuming you can only have odd numbers. It wants four consecutive integers that add up to 8, and -1, 1, 3, 5 add up to 8.

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Im confused

anybody know what this question is asking?

i cant understand...

 

"Find four consecutive odd intergers whos sum is 8"

???

Break down the question.

"Od intengers". Okay, so all 4 numbers must be odd numbers (Like 1, 3, 5 and not 2, 4, 6.)

"whos sum is 8" they all have to count up to 8.

 

With this in mind you may understand why the answer is:

-1, 1, 3, 5

 

If you count that all up, you will see it equals 8. (-1+1 = 0. 3+5 = 8)

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