For and While loops

[InVeyd]

Need help with this one. Every multiples of 3 should be "Wowza" and "Cowza for 5's.
 

12Wowza4CowzaWowza78WowzaCowza11Wowza1314WowzaCowza16

... etc up to 100

Edited April 8, 2015 by prolemur
code tags :)

[minibois]

Need help with this one.

You.. You only want to know the difference?

I believe for loops are like.. For everyone instance of something

(Lets say for example, for every player in a game, it happens once.)

And while loops, happen while something is true.

Example: while there is more than 2 players in game 

 

I believe it works like that

[VioDuskar]

while (condition)

{do this thing}

 

for(initializer; break condition; incrementor)

{do this thing}

Edited April 8, 2015 by alpenwasser
code tags :)

[VioDuskar]

any while can be a for, and any for can be a while. for example, a program that counts to 30, and prints what X is.

for(x=0;x != 30;x++){cout << X << endl;} x=0while (x != 30){x++cout << X << endl;}

 

oh, this in in C++ BTW.

in normal C the only change would be that the line

 

cout << X << endl;

would become:

 printf (" %d  \n" ,X );

Edited April 8, 2015 by alpenwasser
code tags :)

[SIGSEGV]

A while loop does something as long as a condition is true.

 

A for loop goes through a list of sorts until the list finishes.

[VioDuskar]

Need help with this one. Every multiples of 3 should be "Wowza" and "Cowza for 5's.

... etc up to 100

 

Follow your Thread.

you need a while loop, with if statements in it.

 

you also need to use the modulus operator "%" which gives the remainder of an operation.

 

so 6%3= 06%4= 266%11= 010%4= 2

 

understand?

your program needs to use the modulus operator to detect when a multiple is divisable by 3 and 5, so the modulus would yield 0 when those conditions are met.

 

if (x%3 = 0){cout<< wowza}

Edited April 8, 2015 by alpenwasser
code tags :)

[vorticalbox]

what language?

[manon_gfx]

Ah the good old fizzbuzz test: http://c2.com/cgi/wiki?FizzBuzzTest

 

 

What you'll need to know about for this program is the following:

- If statements

- The modulo operator

- Loops (both for and while loop will work)

 

I always recommend programming in baby steps. How big a baby step is, depends on how experienced you are.

Since I see that you are just beginning let's take really small steps


first let's write a program, that checks if a number is divisible by three.
We can simply use the modulo operator and an if statement for this:
 

int number = 6;if(number % 3 == 0) //check if the number is divisible by 3  printf("This number is divisible by 3!\n");

no let's take that program, and chang it so first we check if it's divisble by 3, and if it's not if it's divisible by 5
 

int number = 10;if(number % 3 == 0) //check if the number is divisible by 3  printf("This number is divisible by 3!\n");else if(number % 5 == 0) //if it's not, check if it's divisible by 5  printf("This number is divisible by 5!\n");

Now a bit more tricky we have to know if it's divisible by both 3 and 5. Naturally you would just add another else if to the end, but that won't work. That is because the program will find it's divisible by 3, and then skip over the other checks, so we have to check for that first.
 

int number = 30;if(number % 15 == 0) //we do the modulo of 15 here, because any number that is divisible by both 3 and 5, is divisible by 15 printf("this number is divisible by both 3 and 5!\n");else if(number % 3 == 0) printf("this number is divisible by 3!\n");else if(number % 5 == 0) printf("this number is divisible by 5!\n");

Now we have to put this in a loop to check a bunch of numbers. I'll show how to do that using a while loop.

int number = 1; //the starting numberwhile(number <= 100) //only run while we haven't printed 100 values{  int number = 30;  if(number % 15 == 0)  //check if the number is divisible by both 3 and 5    printf("this number is divisible by both 3 and 5!\n");  else if(number % 3 == 0) //check if the number is divisible by 3    printf("this number is divisible by 3!\n");  else if(number % 5 == 0) //check if the number is divisible by 5    printf("this number is divisible by 5!\n");   number = number + 1; //increment the number by 1}

This program doesn't fulfill all the requirements yet, but can be easily modified to do so

Edit: code tags

PS: this code is writing in C, but is also valid C++, I am not sure what language you are using, but the concepts will be the same

[Kingofpants]

Batch script

@[member='Echo'] offfor /l %%i in (1,1,100) do (set /a "is3=%%i%3"set /a "is5=%%i%5"set "return=%%i"if %is5% equ 0 set "return=Wowza"if %is3% equ 0 set "return=Cowza"if %is5%%is3% equ 11 set "return=WowzaCowza"echo %return%)

[AtlasComputers]

Thought i would do it in PHP for you.

<?php	for($i = 1; $i < 101; $i++)	{		print $i;		if($i%3 == 0) print ' Wowza';		if($i%5 == 0) print ' Cowza';		print '<br />';	}?>

[Stuff_]

They hardly teach the modulo operand in school, it's quite funny.

 

The other day my friend wanted to write a program that prints out even numbers, up to however many the for loop condition was. 

 

I was like, errr.

 

if (number%2 ==0) 

  printf("Even\n");

else 

  printf("odd\n");

 

He's in a beginning java class. But either way, I was hardly taught it. I figured it out myself.

[shujin]

f1=0f=0var array = [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31,32,33,43,35,36,37,38,39,40,41,42,43,44,45,46,47,48,49,50,51,52,53,54,55,56,57,58,59,60,61,62,63,64,65,66,67,68,69,70,71,72,73,74,75,76,77,78,79,80,81,82,83,84,85,86,87,88,89,90,91,92,93,94,95,96,97,98,99,100]f=array.lengthf1=f-1z=0g=0while (z<f1) {g=array[z]if (g%3==0 && g%5==0) {array[z]="WowzaCowza"} elseif (g%3==0) {array[z]="Wowza"} elseif (g%5==0) {array[z]="Cowza"}document.write(array[z])document.write("</br>")z++} 

I would do it like this in javascript but keep in mind that there is a lot of solution to this problem. you don't need to set all var to 0 just the z it's more of a not for myself

[madknight3]

They hardly teach the modulo operand in school, it's quite funny.

 

The other day my friend wanted to write a program that prints out even numbers, up to however many the for loop condition was. 

 

I was like, errr.

 

if (number%2 ==0) 

  printf("Even\n");

else 

  printf("odd\n");

 

He's in a beginning java class. But either way, I was hardly taught it. I figured it out myself.

 

Most beginners classes assume no prior programming knowledge so all the basics are usually mentioned. The modulo operator is likely shown when the basic operations are shown. It's common to mention it after or along with the division operator. At a minimum they should tell you what it does with examples. They may or may not show common uses for it because they may want students to figure that out on an assignment (like the even/odd example).

 

Problem solving is part of programming after all and many times you need to use what you've learned in ways you weren't taught.

[Stuff_]

I'm well past my beginning classes now though. Spring 2016, I'll have my BS in CS with concentrations in Software Eng and Comp info and Secu.

 

I just don't recall using modulo on any assignments/hws. Maybe it's just been a while and my memory sucks. 

[madknight3]

I'm well past my beginning classes now though. Spring 2016, I'll have my BS in CS with concentrations in Software Eng and Comp info and Secu.

 

I just don't recall using modulo on any assignments/hws. Maybe it's just been a while and my memory sucks. 

 

Learning on your own is also an important skill for programmers

 

It's entirely possible it just wasn't covered for you, it just seems odd to me. If you had a "Beginners Java/Python/whatever language" textbook for that class, I would guess it was at least covered there.

 

Either way, good luck on the rest of your degree. 

[Stuff_]

I definitely agree. I learned it myself because it was useful (at least for the projects I was involved with) a few times.

[Art Vandelay]

if(number % 15 == 0) //we do the modulo of 15 here, because any number that is divisible by both 3 and 5, is divisible by 15

 

This seems like premature optimization. It'd probably be better if you wrote if (number % 3 == 0 && number % 5 == 0). A decent compiler should reuse the value of number % 3 and number %5 in the next two checks.

[AtlasComputers]

f1=0f=0var array = [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31,32,33,43,35,36,37,38,39,40,41,42,43,44,45,46,47,48,49,50,51,52,53,54,55,56,57,58,59,60,61,62,63,64,65,66,67,68,69,70,71,72,73,74,75,76,77,78,79,80,81,82,83,84,85,86,87,88,89,90,91,92,93,94,95,96,97,98,99,100]f=array.lengthf1=f-1z=0g=0while (z<f1) {g=array[z]if (g%3==0 && g%5==0) {array[z]="WowzaCowza"} elseif (g%3==0) {array[z]="Wowza"} elseif (g%5==0) {array[z]="Cowza"}document.write(array[z])document.write("</br>")z++} 

I would do it like this in javascript but keep in mind that there is a lot of solution to this problem. you don't need to set all var to 0 just the z it's more of a not for myself

 

 

There is so much unneeded excess and confusing code here, this can be achieved in a mere few lines, as i have done.

<script type="text/javascript">	for(var i = 1; i < 101; i++)	{		document.write(i);		if(i%3 == 0) document.write(' Wowza');		if(i%5 == 0) document.write(' Cowza');		document.write('<br />');	}</script>

[shujin]

 

There is so much unneeded excess and confusing code here, this can be achieved in a mere few lines, as i have done.

<script type="text/javascript">	for(var i = 1; i < 101; i++)	{		document.write(i);		if(i%3 == 0) document.write(' Wowza');		if(i%5 == 0) document.write(' Cowza');		document.write('<br />');	}</script>

I'm usually saving all var for other purpose so I kept that habits sorry

[manon_gfx]

This seems like premature optimization. It'd probably be better if you wrote if (number % 3 == 0 && number % 5 == 0). A decent compiler should reuse the value of number % 3 and number %5 in the next two checks.

 

Sorry, I am a game/graphics programmer. I do these little things without even really thinking about them

[cubercaleb]

any while can be a for, and any for can be a while. for example, a program that counts to 30, and prints what X is.

 

for(x=0;x != 30;x++){cout << X << endl;} x=0while (x != 30){x++cout << X << endl;}

This is assuming you are using the standard namespace, which is a bad idea because it makes the code look messy and hard to read. it would be better to replace 

cout << X << endl;

with

std::cout << X << std::endl;

Now it is clear that you are referring to cout and endl from the standard namespace and not something else. Using namespaces is a bad idea, period.