Bash array

[Auser]

declare -a my_array

my_array=()

format() {

      my_array+=("element")

}

export -f format

for x in 1 2 3 4 5 6 7 8 9; do

     format

done

echo ${my_array[*]}

Why is there no elements on list when I try and print them out with echo. Should there be 9x "element" ? 

[unijab]

unset my_array
declare -a my_array

my_array=""

format () {

      my_array+=("element $1")

}

export -f format

for x in 1 2 3 4 5 6 7 8 9; do

     format $x

done

echo ${my_array[*]}

 

[Auser]

15 hours ago, unijab said:

unset my_array
declare -a my_array

my_array=""

format () {

      my_array+=("element $1")

}

export -f format

for x in 1 2 3 4 5 6 7 8 9; do

     format $x

done

echo ${my_array[*]}

 

Can I use this command aswell?

find / -type d -exec bash -c 'format "$0"' {} \;

will this store results of find in array?

[unijab]

9 hours ago, Auser said:

Can I use this command aswell?

find / -type d -exec bash -c 'format "$0"' {} \;

will this store results of find in array?

 

pretty sure you'll have to pass each item/line to it at a time