Do you know the answer to this math problem?

[laushik]

Please help: 

[Canada EH]

Is that advanced univ math?

quite useless except for a grade.

 

You just gotta find t, then just move it around until t is on the left. Denominator, times both sides, plus or minus you gotta do the opposite.

[Teunvdhanenberg]

A I was thinking like

4,9t2 = 900

4,9t = 30 

t = 30 : 4,9

t = 6,12

[Teunvdhanenberg]

Just now, Canada EH said:

Is that advanced univ math?

No

[Canada EH]

2 minutes ago, Teunvdhanenberg said:

A I was thinking like

4,9t2 = 900

4,9t = 30 

t = 30 : 4,9

t = 6,12

Yeah seems right I guess. Just move the t around. Quite simple, I thought it was going to get into more advanced, gravity and time this that and the other. Perhaps trig and angles.

 

You have to square root the t at the end.

Square Root t^2

[Teunvdhanenberg]

If you know that t = 6,12 you van calculate the rest right?

[Canada EH]

-4.9t^2+900 = -4t  +500

-4.9t^2 = 4t + 500 - 900

-4.9t^2 = 4t - 400
-4.9t^2 / 4t = -400

-4.9t^2 / 4t = -400 x 4

-4.9t^2 / 4t = -3600 

t^2/4t = -3600 / -4.9

t^2/4t = 734.69

t^2/t = 734.69 x 4

t^2/t = 2938.78

t = 2938.78 probably seconds, could be minutes.

[Guest]

Soory, I think this problem is aboot some physics, eh? 

 

Ill be back to try and figure it out. On mobile rn. 

[Canada EH]

13 minutes ago, fpo said:

Soory, I think this problem is aboot some physics, eh? 

 

Ill be back to try and figure it out. On mobile rn. 

Its easier to do on paper, but I refuse to pickup my pen 14inches away and that scrap piece of paper 3' away.

[TetraSky]

Isn't A and B basically just the X and Y of the point where both formulas encounter each other? As in you have to compare them :

Spoiler

 

A) Would be 9.45 seconds
B) Would be 462 meters.
C) Is essentially what I've written

Am I missing something here? Even DESMOS gives me the same result when entering both formulas. 

Spoiler

 

[laushik]

1 minute ago, TetraSky said:

Isn't A and B basically just the X and Y of the point where both formulas encounter each other?

  Reveal hidden contents

 

A) Would be 9.45 seconds
B) Would be 462.19 meters.
C) Is essentially what I've written

Am I missing something here? Even DESMOS gives me the same result when entering both formulas. 

  Reveal hidden contents

 

You are correct!!!

[TetraSky]

1 minute ago, laushik said:

You are correct!!!

Yay I have no life.

[Canada EH]

1 hour ago, TetraSky said:

Isn't A and B basically just the X and Y of the point where both formulas encounter each other? As in you have to compare them :

  Reveal hidden contents

 

A) Would be 9.45 seconds
B) Would be 462 meters.
C) Is essentially what I've written

Am I missing something here? Even DESMOS gives me the same result when entering both formulas. 

  Reveal hidden contents

 

But what is t?

[dgsddfgdfhgs]

1 minute ago, Canada EH said:

But what is t?

in physics, t must be time in seconds

[Canada EH]

1 minute ago, dgsddfgdfhgs said:

in physics, t must be time in seconds

I did all that work, and I want to know what t is, I want to know, I want to know, I want to know

Quote

t = 2938.78

LOL

[mxk]

1 hour ago, TetraSky said:

Yay I have no life.

no no you're a genius

[TetraSky]

8 hours ago, Canada EH said:

But what is t?

t is just an unknown. It represent the number of seconds after the crate was dropped in this particular case.
It can be replaced by literally any other letters as long as you remember what it's used for, I used x for it because x is easier to work with than t, especially on paper where t could be mistaken for +.
Usually, we use a graph with an x and y axis, x representing the time(seconds, days, years) and y as the number of something (like meters). But it's not absolutely limited to that and can be anything else. This is high school math.
It could technically be physic, but this sort of question is math since they don't require you to calculate things like the force/speed at which the crate is falling

[Canada EH]

yeah but you had to find what t was.

[TetraSky]

5 hours ago, Canada EH said:

yeah but you had to find what t was.

And t was 9.45 seconds, the answer to A). (or 9.4524570637389136247310113144392... seconds, if you want to more a bit more precise)

You don't lose points for using a different unknown variable in your calculations than the one in the problem itself, as long as you identify it somewhere with something like x = time in seconds(t)  ///  y = height in meters(h).
With problems like these, it's nice to have graph papers so you can create a visual interpretation of the formulas you're working with, of which students should be allowed to use during their exams as well, if their school isn't complete garbage anyway. (Heck, these days, the high schools here allow students to have an actual "cheat sheet" during their math exams, for them to write various formulas and other crap they may have forgotten on it... ridiculous)

[Big Boi Lime]

This just makes me realise how bad my maths is...