Java errors

[ToastFromDiscord]

So, I'm trying to calculate the theoretical number of tweets possible in Java, but I keep getting the error "cannot convert type double to int" but as far as I know, there are no doubles in this code. Please help?

public class Main {

  public static void main(String[] args) {
   int x = 1;
   int y = 0;
   while(x<=280)
   {
     y = y+Math.pow(1114112,x);
     x=x+1;
   }
   System.out.println(y);
  }
}

[Max Day]

Are you using swing?

[ToastFromDiscord]

So I figured it out, but it overflows to all hell... What should I do to calculate it?

[tikker]

Math.pow returns a double. Either cast to int or make y a double. Also with such large powers you are bound to overflow. Use BigInteger for this: https://stackoverflow.com/questions/11317875/finding-really-big-power-of-a-number

 

[Fetzie]

21 hours ago, ian1467 said:

So, I'm trying to calculate the theoretical number of tweets possible in Java, but I keep getting the error "cannot convert type double to int" but as far as I know, there are no doubles in this code. Please help?

public class Main {

  public static void main(String[] args) {
   int x = 1;
   int y = 0;
   while(x<=280)
   {
     y = y+Math.pow(1114112,x);
     x=x+1;
   }
   System.out.println(y);
  }
}

Math.pow returns the data type "Double", you are trying to assign that value to the integer value y.

[Guest]

(Mobile site doesn’t have code formats available...  )

 

y = y + (int) math.pow(//equation);

 

the (int) tells the compiler to change the value of math.pow to be an integer type. It works that way in c# as well. 

 

Java cast Source: 

https://stackoverflow.com/questions/9102318/cast-double-to-integer-in-java

[BlueChinchillaEatingDorito]

On 6/9/2018 at 11:10 AM, ian1467 said:

So, I'm trying to calculate the theoretical number of tweets possible in Java, but I keep getting the error "cannot convert type double to int" but as far as I know, there are no doubles in this code. Please help?

public class Main {

  public static void main(String[] args) {
   int x = 1;
   int y = 0;
   while(x<=280)
   {
     y = y+Math.pow(1114112,x);
     x=x+1;
   }
   System.out.println(y);
  }
}

 

Remember to use code tags next time to make it easier for us to read. 

My best guess is that this line is causing the problem:

 y = y+Math.pow(1114112,x);

as Math.pow returns a double data type. You'll can cast double to int but adding (int) in front or using the intValue() method.

 y = y + (int) Math.pow(1114112,x);

 y = y + (Math.pow(1114112,x)).intValue();

 

[colonel_mortis]

1114112²⁸⁰ is a truly gargantuan number (1694 decimal digits according to wolfram alpha), and is much larger than even 1114112²⁷⁹ (which "only" has 1688 digits), so the answer is 1.38 * 10¹⁶⁹³ (which is just 1114112²⁸⁰). If you really want to work it out exactly, there are no primitive datatypes in Java that can store numbers that big (double is limited to about 10³⁰⁸), but you can use BigInteger to calculate it (which has a .pow and a .add method).