Jump to content

Quick question for the group. As a electrician I understand that running a load at lower voltage will raise the current as per ohms law ( voltage and current being inversely proportionaL ) .A fixed wire gauge running at a higher current will produce more heat on said wire. For example an air conditioner motor with a multi voltage tap  either 240v or 120v will draw twice the amperage at the 120 v tap  then the higher 240v tap. Going with the higher voltage produces less heat on the wire. The question is why does under volting produce lower thermal output, isn't wattage based on work done v x a + wattage  and if the efficiency stays the same the thermal output is the relation of wattage and efficiency no matter how your wattage is derived ( lower voltage and higher amperage or vice versa )? For example 1 volt at 10 amps is 10 watts  and 10 volts at 1 amp is 10 watts. Both loads in my profession would produce the same thermal output given the efficiency stays the same . One would think the work done by the cpu would be the same as the load stays the same or does the load decrease because the cpu slows down?  Im just trying to satisfy my ocd mind and get this straigt . Thanks for helping me understand the difference as I am defiantly not a electronic technician.

Link to comment
https://linustechtips.com/topic/919452-undervolting/
Share on other sites

Link to post
Share on other sites

Actually, CPUs pull the same current regardless of voltage (unless it crashed or something) because it just wants electrons to run through the transistors. That's why undervolting increases the efficiency of the CPU.

CPU: i7-2600K 4751MHz 1.44V (software) --> 1.47V at the back of the socket Motherboard: Asrock Z77 Extreme4 (BCLK: 103.3MHz) CPU Cooler: Noctua NH-D15 RAM: Adata XPG 2x8GB DDR3 (XMP: 2133MHz 10-11-11-30 CR2, custom: 2203MHz 10-11-10-26 CR1 tRFC:230 tREFI:14000) GPU: Asus GTX 1070 Dual (Super Jetstream vbios, +70(2025-2088MHz)/+400(8.8Gbps)) SSD: Samsung 840 Pro 256GB (main boot drive), Transcend SSD370 128GB PSU: Seasonic X-660 80+ Gold Case: Antec P110 Silent, 5 intakes 1 exhaust Monitor: AOC G2460PF 1080p 144Hz (150Hz max w/ DP, 121Hz max w/ HDMI) TN panel Keyboard: Logitech G610 Orion (Cherry MX Blue) with SteelSeries Apex M260 keycaps Mouse: BenQ Zowie FK1

 

Model: HP Omen 17 17-an110ca CPU: i7-8750H (0.125V core & cache, 50mV SA undervolt) GPU: GTX 1060 6GB Mobile (+80/+450, 1650MHz~1750MHz 0.78V~0.85V) RAM: 8+8GB DDR4-2400 18-17-17-39 2T Storage: HP EX920 1TB PCIe x4 M.2 SSD + Crucial MX500 1TB 2.5" SATA SSD, 128GB Toshiba PCIe x2 M.2 SSD (KBG30ZMV128G) gone cooking externally, 1TB Seagate 7200RPM 2.5" HDD (ST1000LM049-2GH172) left outside Monitor: 1080p 126Hz IPS G-sync

 

Desktop benching:

Cinebench R15 Single thread:168 Multi-thread: 833 

SuperPi (v1.5 from Techpowerup, PI value output) 16K: 0.100s 1M: 8.255s 32M: 7m 45.93s

Link to comment
https://linustechtips.com/topic/919452-undervolting/#findComment-11269935
Share on other sites

Link to post
Share on other sites

The thing with CPUs is that they're entirely reliant on voltage levels for signaling. The work is really to get the voltage levels to the correct place. And as long as the threshold is met, the CPU is fine.

 

It also helps to know how transistors work. They don't really act as resistive loads per se (if you're doing paper napkin analysis, they have no resistance). For CPUs, it's typically MOSFETs or an evolution of them. And these act more or less like a faucet, with the voltage affecting how much the handles are turned and the current being the water that flows through. So undervolting actually decreases the current flowing through the system. And less current running through means less heat is generated because everything still has a resistance value to it.

 

Also the Power = Capacitance (of a transistor) * Voltage ^ 2 * frequency came from https://software.intel.com/en-us/blogs/2009/08/25/why-p-scales-as-cv2f-is-so-obvious-pt-2-2

Link to comment
https://linustechtips.com/topic/919452-undervolting/#findComment-11270062
Share on other sites

Link to post
Share on other sites

12 hours ago, jjesse47 said:

As a electrician I understand that running a load at lower voltage will raise the current as per ohms law

???O.o

 

I = U / R, decreasing the voltage will decrease the current.You are mistaking ohms law with P = U * I (where you can have same power with lower voltage at higher current).I'm shocked that nobody has mentioned this yet.

Link to comment
https://linustechtips.com/topic/919452-undervolting/#findComment-11271478
Share on other sites

Link to post
Share on other sites

5 hours ago, MyName13 said:

???O.o

 

I = U / R, decreasing the voltage will decrease the current.You are mistaking ohms law with P = U * I (where you can have same power with lower voltage at higher current).I'm shocked that nobody has mentioned this yet.

It seems like the OP was talking about induction motors and similar, where amperage can increase as voltage declines.

Link to comment
https://linustechtips.com/topic/919452-undervolting/#findComment-11272189
Share on other sites

Link to post
Share on other sites

Create an account or sign in to comment

You need to be a member in order to leave a comment

Create an account

Sign up for a new account in our community. It's easy!

Register a new account

Sign in

Already have an account? Sign in here.

Sign In Now

×