URGENT! I need help!

[DanielMDA]

So, tomorrow I have a Math test, and in my Guide, I cant figure out an exercise. Can you help me? Its Analytic Geometry. But I cant find it on a teachers book. I need to know if you need to square a number.

 

The exercise is about parable equations. The Directive too. The exercise is: y-2x-2=0 with focal poiunts beign (2,-2) However, I dont know if it should be 2x or 2x²? Mathematically in this case what should it be?

And in the second exercise, quote: Find the intersection between the parables -x²+4x+y-2=0 and x²-y+2=0? How would you solve that? Any info is appreciated.

 

TO A MOD: Please dont change it to another place, I need this to be seen by as many people as possible. Thank you.

[QuantumBit]

People see it equally either place, since they usually look at the side.

[Fokus]

 

3 minutes ago, Abyssal Radon said:

Ultimately your trying to figure out the points that the equation's intersects? Your wording is strange, anyway I can try and solve it and take a picture of my work. Assuming that would help, your doing a Analytical Geometry course in high school or college? 

It looks like HS work I was doing this type of math in high school.

[DanielMDA]

3 minutes ago, Abyssal Radon said:

Ultimately your trying to figure out the points that the equation's intersects? Your wording is strange, anyway I can try and solve it and take a picture of my work. Assuming that would help, your doing a Analytical Geometry course in high school or college? 

I am translating directly from Spanish, I am sorry.

[DanielMDA]

2 minutes ago, coyotetracker said:

 

It looks like HS work I was doing this type of math in high school.

I am in HS

[DanielMDA]

4 minutes ago, Abyssal Radon said:

Ultimately your trying to figure out the points that the equation's intersects? Your wording is strange, anyway I can try and solve it and take a picture of my work. Assuming that would help, your doing a Analytical Geometry course in high school or college? 

High School

[Fokus]

11 minutes ago, DanielMDA said:

So, tomorrow I have a Math test, and in my Guide, I cant figure out an exercise. Can you help me? Its Analytic Geometry. But I cant find it on a teachers book. I need to know if you need to square a number.

 

The exercise is about parable equations. The Directive too. The exercise is: y-2x-2=0 with focal poiunts beign (2,-2) However, I dont know if it should be 2x or 2x²? Mathematically in this case what should it be?

And in the second exercise, quote: Find the intersection between the parables -x²+4x+y-2=0 and x²-y+2=0? How would you solve that? Any info is appreciated.

 

TO A MOD: Please dont change it to another place, I need this to be seen by as many people as possible. Thank you.

I don't know if this will help but I found this. http://www.geteasysolution.com/y-2x-2=0 from me looking at the answer I think it's 2x. but I'm not 100%

 

[Fokus]

9 minutes ago, coyotetracker said:

I don't know if this will help but I found this. http://www.geteasysolution.com/y-2x-2=0 from me looking at the answer I think it's 2x. but I'm not 100%

 

Yeah, I'm pretty sure it's 2X because x is the variable.

[tj_314]

for your second exercise: To find an intersection between two curves means to find all points that belong to curve 1 and curve 2 at the same time. It basically means that you have to solve a system of equations. In your case the two equations are the parabolas you provided. From the second equation, you get y = x^2 + 2. you plug it into the first equation and you get -x^2 + 4x + x^2 + 2 - 2 = 0 which simplifies to 4x = 0 and therefore x = 0. There is only 1 intersection point at x = 0. now, you just calculate y value from any of your two equations. since we already know that y = x^2 + 2, we get y = 2. The intersection is at x=0, y=2.

[tj_314]

more readeable form:

(1) -x² + 4x + y - 2 = 0

(2) x² - y + 2 = 0 --> y = x² + 2

======================

-x² + 4x + y - 2 = -x² + 4x + (x² + 2) - 2 = 4x = 0 --> x = 0

y = x² + 2 = 0² + 2 = 2

intersection at [0, 2]

[WkdPaul]

52 minutes ago, DanielMDA said:

TO A MOD: Please dont change it to another place, I need this to be seen by as many people as possible. Thank you.

Sorry but that's not how it works.

 

Moved to off-topic section

[tj_314]

I do not quite understand what you're asking in the first question, though.

[DanielMDA]

2 hours ago, tj_314 said:

I do not quite understand what you're asking in the first question, though.

If its 2x or 2x squared... It doesnt make sense how its written