C help yet again..

[WorldDominator]

Confession: I don't really know how to code in C

 

I do c# and some java

Close enough tbh

[rubenroy]

I think using fgets() for console input is overkill. Have you tried :

scanf("%[^\n]",string_variable);

This will keep reading till a newline is found. IIRC %s will only read single words.

[MikeD]

I think using fgets() for console input is overkill. Have you tried :

scanf("%[^\n]",string_variable);

This will keep reading till a newline is found. IIRC %s will only read single words.

 

Huh, I guess I forgot scanf took that kind of regex as a format!

[WorldDominator]

I think using fgets() for console input is overkill. Have you tried :

scanf("%[^\n]",string_variable);

This will keep reading till a newline is found. IIRC %s will only read single words.

I haven't seen anything like that before

I did find another solution though. Thanks guy!

[random314]

The problem is that fgets() doesn't strip the newline from the input, you need to do it yourself (for example using strok(string_with_newline, "\n")) then you should be OK. 

 

Also:

• I don't think the fflush()es are necessary (I haven't tested it though)
• You can use the sizeof() operator in your fgets() statements (eg: fgets(list[n].string, sizeof(list[n].string), stdin)

[WanderingFool]

Yea, what @random314 said you have a new line character at the end of the string.

 

You could also do list[n].first[strlen(list[n].first)-1] = '\0'; assuming you check that first is also >= 1

 

One last point using fgets it is very important that you get the array amount right.  Your fgets for first can overflow, since you can write 21 characters to an 16 character array