Maths help

[Gofspar]

I need the ones that aren't answered answered.

 

I have to finish this shit before I can do finals.

 

[colonel_mortis]

I won't tell you the answers, but I will give you some help on some of the questions:

11) The gradient of a perpendicular line is -1÷the gradient of the other line, and the gradient of the other line can be found by doing change in y÷change in x

12) x^-y=1÷x^y - the minus sign means that it flips to the other side of the fraction

13) Complete the square to find the turning point of the graph

14) Just add and subtract them to find an expression in the form ax²+bx+c

15) y=mx+c. You know y, m and x, so solve it for c

17) Common denomintaor

18) The y axis has the equation x=0

19) Multiply them by something such that you can add them together to cancel one of the letters

[Gofspar]

I won't tell you the answers, but I will give you some help on some of the questions:

11) The gradient of a perpendicular line is -1÷the gradient of the other line, and the gradient of the other line can be found by doing change in y÷change in x

12) x^-y=1÷x^y - the minus sign means that it flips to the other side of the fraction

13) Complete the square to find the turning point of the graph

14) Just add and subtract them to find an expression in the form ax²+bx+c

15) y=mx+c. You know y, m and x, so solve it for c

17) Common denomintaor

18) The y axis has the equation x=0

19) Multiply them by something such that you can add them together to cancel one of the letters

I bucked up and did most of them and stopped being lazy.

 

Thanks for the help though.

[Gofspar]

11, 12 and 13?

[FloRolf]

11

slope of line n is (15-12)/(4-7)= -1

 

slope of perpendicular line is -1/n = 1

 

 

12

Just put negative exponents up or down depending on where they are.

That makes:

9n^7 / 12m^7 p²

 

 

13.

P=-25d²+500d

P'=-50d+500

500=50d

d=10