Math help(easy)

[ManOfDisguise]

Ok I think I knew how to do this but now I forgot anyway for homework I have to do this:

(also sorry for the large spaces didnt know how to do the line to make it closer)

 

 

x+2   - 1 = 3x2(the small 2 as like squared) + x + 9     -   x-2

-----          --------------------------------------------------        -----

x-2                                3( x2-4)                                      x+2

 

 

 

 

Now can you pls tell me how to do it too? Here is how I think it should be done(faint memories)

 

so i mulitply all of the top numbers with all of the bottom numbers that aren"t there - for example: (x+2) (x+2) + 3 (x2-4) - this is the first fraction im talking about x+2 it already has x-2 down so ill leave that out and multiply it with the other lower

                                                                                                                                                                                                                                                         -----

                                                                                                                                                                                                                                                          x-2

numbers: 3(x2-4) and x+2. and then ill do the sam for the other fractions. is this the right way to do it?

                                                                                                                                                                                                                                                       

[Nineshadow]

3(2x -4) is 6(x-2)

[ManOfDisguise]

3(2x -4) is 6(x-2)

no sorry i meant the x2 as in x squared

[ZacDaMan72]

Wolfram|Alpha, my friend. For squared numbers a "^" is placed between the x value and the power eg: x^2. Answer is

The way you typed it is illegible, so i probably got it wrong. PLEASE post a picture of the question.

[Prokart2000]

i HATE algebra!

[MrTomnus]

@ManOfDisguise Wow, that's one question you've got there... I just tried doing some working for it and I didn't really want to carry on. Anyway, here's what I did:

 

Give the two fractions on the right a common denominator. So in this case, multiply the denominators together to get 3(x^2 - 4)(x + 2). Then apply the same change to the numerators of each fraction, multiplying by the alternate denominator, and then subtract them to get a single fraction.

 

But then there's a hell of a lot of multiplication involved... It looks kinda horrid to me. Are you sure you're not supposed to use polynomial division or partial fractions or something? But anyway if you're up for cross multiplying those fractions, then it should work and you'll get an answer for x. But you'll likely have to use the quadratic formula or factorise it.

 

Here is what I did:

 

[TideRower]

Do you mean something like:

 

(x+2)/(x-2) -1=(3*x^2 + x + 9)/(3*x^2 - 4)-(x-2)/(x+2) ?

 

I suppose you want to simplify the equation and get a polynomial equation as the result.

 

You just need to multiply the equation with the greatest common divisor of the denominators (or a multiple of it). This eliminates all the fractions.

The rest is just multiplication and simplification.

 

The solution should be:

x^3 - 35*x^2 - 4*x + 12 = 0

[Nineshadow]

x^2 - 4 = (x +2)(x-2)

 

This is soo easy.Come on.

 

x is equal to 27.

[Nineshadow]

There you go.I might have fucked up some addition,but you would fix that.

[ManOfDisguise]

There you go.I might have fucked up some addition,but you would fix that.

thanks a lot! i just want to ask  if u look in the third from bottom row u have -12x + 12x at the very right dont those get cancelled out?and also where did u get the -3 in the 2nd from bottom row?

[Nineshadow]

thanks a lot! i just want to ask  if u look in the third from bottom row u have -12x + 12x at the very right dont those get cancelled out?and also where did u get the -3 in the 2nd from bottom row?

That's "-12  +   12x" ,not -12x + 12x.

And the -3 comes from :

9 -12 = -3 

[ManOfDisguise]

That's "-12  +   12x",not -12x + 12x.

And the -3 comes from :

9 -12 = -3 

oh sorry im so stupid lol i dunno how i saw an x there lol

[Nineshadow]

oh sorry im so stupid lol i dunno how i saw an x there lol

np.

[terrytek]

Are you trying to factor the equations? Well, you have a quadratic equation: 3x^2+x+9. Factor that first. Report back.

 

BTW, I'm taking AP Algebra, so I know what I'm doing.

[T.Vengeance]

Are you trying to factor the equations? Well, you have a quadratic equation: 3x^2+x+9. Factor that first. Report back.

 

BTW, I'm taking AP Algebra, so I know what I'm doing.

Lol person taking AP algebra who "knows what he's doing" doesn't realize that the above said equation doesn't pass the discriminant test.

[TideRower]

Lol person taking AP algebra who "knows what he's doing" doesn't realize that the above said equation doesn't pass the discriminant test.

 

Every polynom can be factorized . You just need to use complex numbers.

[T.Vengeance]

Every polynom can be factorized . You just need to use complex numbers.

I know, but I'm pretty sure he needs real solutions.

[terrytek]

Every polynom can be factorized . You just need to use complex numbers.

Exactly. See, @T.Vengeance? I told ya so. It can be factorized.

[werto165]

Are you trying to factor the equations? Well, you have a quadratic equation: 3x^2+x+9. Factor that first. Report back.

 

BTW, I'm taking AP Algebra, so I know what I'm doing.

So americans don't just do maths, its split up into different sections then?

[TideRower]

I know, but I'm pretty sure he needs real solutions.

It shouldn't be a problem, the solutions are the same. But factorizing isn't usefull in this case and makes the whole equation more complex     than it needs to be.

[Nineshadow]

Are you trying to factor the equations? Well, you have a quadratic equation: 3x^2+x+9. Factor that first. Report back.

 

BTW, I'm taking AP Algebra, so I know what I'm doing.

There's no point for that...

[terrytek]

There's no point for that...

Well, there is a point when you  try to simplify.

[Nineshadow]

Well, there is a point when you  try to simplify.

Not here because after you'll simplify you'll have to de-simplify.