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So im 16 and I have a job in IT. (Its great), and my boss asked me some questions to figure out just for fun.

I thought I would ask on some of the questions I can't figure out.

1. What is the significance of the starting value of '10' (10.1.16.0)

2. What term is used to describe a network in this way? (Network 10.1.16.0 /20)

3. If the first 300 available addresses are static what would be the first address available to use with a DCHP range?

 

 

We’ll assign some static addresses as follows:

 

10.1.16.1              Gateway (Firewall)

10.1.16.10            File Server

10.1.16.20            Primary Copier / Printer

 

Other static IP’s will be assigned once you figure out how many printers need them.

 

We may also need some for other network devices (the WIFI infrastructure for example).

 

I’ll setup the DHCP server to distribute addresses for the 10.1.16.0/20 network as well as the old 192.168.111.x network.   The old network will be used by the new phone system using a VLAN.

 

The voice switch for the phone will have an address of 192.168.111.8

 

I’ll probably reserve 300 addresses as static and use DHCP for the rest.

 

If the first 300 available addresses are static what would be the first address available to use with a DHCP range?

What would be the last available address on the network?

What s the broadcast address?

What is the subnet mask in binary?       (Im pretty sure I know the answer since the subnet mask is 255.255.240.0 right)

 

Thanks

 

 

 

Breaking things 1 day at a time

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1. Nothing, its just that 10.0.0.0 is resvered for local network with 192.168.0.0/24 and 172.16.0.0 /20

 

10 is used as you have the most options( about 16 million since its a /8)

 

3. For dhcp range id do something lie 10.1.20.0 - 10.1.17.254 and do all the statics on 10.1.16/24

 

What is your network layout? 10.0.0.0/8?

 

11 minutes ago, TubsAlwaysWins said:

The voice switch for the phone will have an address of 192.168.111.8

No you won't unless everthing is in 193.168.0.0/16

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If the first 300 available addresses are static what would be the first address available to use with a DHCP range? 10.1.16.301 - 10.1.31.254 (best way to do this though would be put the first /24 as its own DHCP pool with DHCP disabled on it for those and use the remaining /21 for DHCP leases)

What would be the last available address on the network? 10.1.31.254

What s the broadcast address? 10.1.31.255

What is the subnet mask in binary?  You are correct, its 255.255.240.0

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Where's a whiteboard when you need one...

 

1. Agreed with above, local address ranges.

2. It's another way of defining a subnet mask. Basically the number of useable addresses on your chosen address range (Also displayed as 255.255.240.0)

So, if I had a network set up with 10.0.0.0/20, my address range would be 10.0.0.1 - 10.0.15.255, meaning I have 16*255 addresses available to clients. 

 

This site has an IP calculator I have used in the past:

 

http://jodies.de/ipcalc?host=10.1.18.16&mask1=20&mask2=28

 

3. As above 

 

 

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6 minutes ago, TubsAlwaysWins said:

1. What is the significance of the starting value of '10' (10.1.16.0)

The entire 10.x.x.x IPv4 block is reserved for private networks.

6 minutes ago, TubsAlwaysWins said:

2. What term is used to describe a network in this way? (Network 10.1.16.0 /20)

Subnetting.

6 minutes ago, TubsAlwaysWins said:

3. If the first 300 available addresses are static what would be the first address available to use with a DCHP range?

10.1.16.1

8 minutes ago, TubsAlwaysWins said:

What would be the last available address on the network?

10.1.31.254

8 minutes ago, TubsAlwaysWins said:

What s the broadcast address?

10.1.31.255

8 minutes ago, TubsAlwaysWins said:

What is the subnet mask in binary?       (Im pretty sure I know the answer since the subnet mask is 255.255.240.0 right)

0b1111 1111 1111 1111 1111 0000 0000

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8 minutes ago, Electronics Wizardy said:

No you won't unless everthing is in 193.168.0.0/16

L3 Switch, my friend :P Can do whatever you want and use 10.0.0.0/8, 192.168.0.0/16, 172.16.0.0/12 if you route them. Your private subnets were also wrong.

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