Simple Math Stuff

[anagiotis567]

Hey Guys! Can someone explain to me what "1." is equal to, in the following expression.

 

Post The Following in this website:http://www.hostmath.com/

 

\frac{0.318471a^2}{((a^2-1.)m^2n^2+1.)^2}

0.

Pppp.s

Thathats what i got when i simpified the ggx(throwbridge-reitz) distribution term using wolframalpha,simplifier.

[CydiaDash]

Not simple for me ... Never seen anything like this before haha

[Blueprint]

What do you mean what '1' is equal to?

[anagiotis567]

What do you mean what '1' is equal to?

not "1", "1."

[Blueprint]

not "1", "1."

What do you mean? What is 1.? Is it a question number? What does the link have to do with it apart from showing the quadratic formula?

[anagiotis567]

What do you mean? What is 1.? Is it a question number? What does the link have to do with it apart from showing the quadratic formula?

Because I couldn't write the formula in the forums,i posted "\frac{0.318471a^2}{((a^2-1.)m^2n^2+1.)^2}" so that you can see the formula on the website.Delete The quadratic equation and paste what i have written to see the  formula.

[Masada02]

The equation you provided is not equal to anything so at this point it is not equal to anything other than itself. Pretty confident you are forgetting some information.

[Blueprint]

Because I couldn't write the formula in the forums,i posted "\frac{0.318471a^2}{((a^2-1.)m^2n^2+1.)^2}" so that you can see the formula in the forums.Delete The quadratic formula and paste what i hav written to understand what i mean.

Ah ok I see, thanks. I still don't understand, are you trying to figure out the roots of that equation using the quadratic formula? Is the equation meant to be equal to 0?

[Masada02]

I'm guessing you want to separate the "1." out of the equation, but to do that we need to know what that formula is equal to. I'm guessing it's 0.

[anagiotis567]

Ah ok I see, thanks. I still don't understand, are you trying to figure out the roots of that equation using the quadratic formula? Is the equation meant to be equal to 0?

the quadratic formula has nothing to do with my question,its there by default.I just don't know what "1." means.

[Sauron]

the quadratic formula has nothing to do with my question,its there by default.I just don't know what "1." means.

 

where do you see "1."?

[Curufinwe_wins]

Hey Guys! Can someone explain to me what "1." is equal to, in the following expression.

 

Post The Following in this website:http://www.hostmath.com/

 

\frac{0.318471a^2}{((a^2-1.)m^2n^2+1.)^2}

Please Help!

0.

1 is always equal to one.

 

The use of 1. in latex and many other written forms is intended to make sure it is distinguishable between a capital i. Other uses of a number followed by a period is to indicate that the last digit is in fact the last significant digit. For example the number 1000, could have 1,2,3 or 4 sig figs, but saying 1000. means it has 4.

[Blueprint]

the quadratic formula has nothing to do with my question,its there by default.I just don't know what "1." means.

A period/dot on the lower half of the line usually denotes multiplication so for example 2.3 = 6.  Also x.y=xy 

[Curufinwe_wins]

Ah period/dot on the lower half of the line usually denotes multiplication so for example 2.3 = 6.  Also x.y=xy 

2.3 =/= 6. That is AWFUL form, never ever ever write math like that. This isn't on the lower half... This is on literally the bottom of the line.

 

The reason you sometimes write x.y instead of x*y is to make sure people know you mean the product of "x" and "y" not the object "xy".

[anagiotis567]

A period/dot on the lower half of the line usually denotes multiplication so for example 2.3 = 6.  Also x.y=xy 

but there's nothing to multiply to,there is a closing bracket.

[anagiotis567]

where do you see "1."?

\frac{0.318471a^2}{((a^2-1.)m^2n^2+1.)^2}

[Curufinwe_wins]

but there's nothing to multiply to,there is a closing bracket.

It is JUST THE NUMBER 1. No tricks to it. It's a convention that holds no actual meaning.

 

Proof: Wolfram Alpha has fully featured LaTeX support. It expands that fraction as if 1. is just 1, because that is what it is.

 

http://www.wolframalpha.com/input/?i=%5Cfrac%7B0.318471a%5E2%7D%7B%28%28a%5E2-1.%29m%5E2n%5E2%2B1.%29%5E2%7D

[Masada02]

1 is always equal to one.

 

The use of 1. in latex and many other written forms is intended to make sure it is distinguishable between a capital i. Other uses of a number followed by a period is to indicate that the last digit is in fact the last significant digit. For example the number 1000, could have 1,2,3 or 4 sig figs, but saying 1000. means it has 4.

Here I am simplifying this whole complicated mess and then you tell me. That's pretty cool though, never knew that. Never seen it used either since equations are always taken as literally as possible negating the need to clarity. Still interesting to know none-the-less.

[ThinkWithPortals]

What the hell do you mean, "simple math?!"

[Curufinwe_wins]

Here I am simplifying this whole complicated mess and then you tell me. That's pretty cool though, never knew that. Never seen it used either since equations are always taken as literally as possible negating the need to clarity. Still interesting to know none-the-less.

I started doing it as well, until I realized he literally meant what is "1."

 

I only had two terms left in the expansion (and was compressing them).

[Masada02]

What the hell do you mean, "simple math?!"

It's just algebra. Albeit stupid, multiple unknowns algebra, but still algebra.

[Sauron]

\frac{0.318471a^2}{((a^2-1.)m^2n^2+1.)^2}

 

It's just the way calculators and software will write integers if there are decimals in the equation with them. It's abbreviated for 1.000