Programming class need help!

[grant N]

can some one please help me with this?

[Guest]

What part are you looking help for?

Everything? Just the start? middle? End?

Thats the thing w/ programming, You need to learn it yourself, You need to put in the research and teach yourself.\

 

Offnote on coding in general 

Coding isn't something teachers teach you how to do

Its something you learn how to do from experience. You don't learn from another person telling you what to do, then you won't know what to do when your lost/confused.

You need to learn how to do it yourself, after school, learn when to use certain things, when not too.  

Now I'm no coding expert, However, I have a very wise friend who did try coding and he said that exact thing.

[grant N]

i just don't know where to start at

[spartaman64]

first form out pseudocode so use words to describe what the program will do

 

Alt+MAlt+N

[Dabasepc]

can some one please help me with this?

 

quit your class already if u need help for this

[nickl]

can some one please help me with this?

Do you want us to tell you what to type, or give you a general idea of what you have to do?

[1B0Y]

Can't exactly help you without "Demo0107"

[nickl]

Anyway, here is an overview of what you have to do:

1. Define some variables for what the user inputs, and whatever you want to calculate
2. (I assume you are using the command line to do this, and don't want to do something with windows or whatever): Use cout statements to ask the user what their gallons, starting mileage, ending mileage.
3. Use cin statements to let the user enter them, and to assign the values that they type to the variables from step 1
4. Do some math to calculate the mileage.
5. Use an if to check if the entered mileage is -1 and if so, have the program print out totals for the miles and gallons, calculate an average mpg, and then to return 0
6. You should put all of this into a infinite loop so then it will run until the user enters -1 as the miles used, and will then return 0 after printing.

This program is sorta just testing your problem solving skills, as well as top down design etc.

 

A few notes: make sure you use #include iostream if you want to use cout and cin statements, as they won't work otherwise it won't work.

I would suggest making variables that represent the the values for starting mileage, ending mileage, diff in mileage, gallons used, total gallons, and total distance.

I probably am forgetting something, so think about it yourself.

[Nuluvius]

You should prob explain what you need help with rather than posting a sideways picture that no one will read.

 

Agreed, I sure as hell am not going to bother reading that and trying to divine what it is exactly that you seem to be after. Show some effort and perhaps others may reciprocate.

[Blade of Grass]

Moved to Programming and Software Design. 

[Guest]

Here, now someone might help without the fear of breaking their neck. I would help but I don't know C++

[vorticalbox]

get gallons used

if -1 exit program

else

get start mileage

get end mileage

mile driven = end - start

m/g = mile driven / gallons used

 

 

now code that in c++. might want to check that gallons isn't lower than zero and that it is actually a number.

[as96]

int main(int argc, const char * argv[]) {        float usedGallons = 0.0f;    int start = 0, end = 0;    int d = 0;    float m = 0.0f;        while(true)    {        std::cout << "Used gallons";        std::cin >> usedGallons;        if(usedGallons == -1)            break;        std::cout << "Start mileage:";        std::cin >> start;        std::cout << "End mileage:";        std::cin >> end;        d = end - start;        m = d / usedGallons;        std::cout << "Result: " << m << std::endl;    }        return 0;}

I wrote it fast and didn't test it but it should work.

[vorticalbox]

 

You just did this guys home work.

[as96]

You just did this guys home work.

It's what he wanted.

[vorticalbox]

It's what he wanted.

now he is gonna pass a class he has no idea about.

[deviant88]

I dont understand this is one of the eassiest things in C++ all you deal with is int main and cout/cin and a couple local variables.What help do you need? you want someone to write the code for you ? or some advice what is the problem? show us the code you tried to write so far and where you are stuck.

If you didnt try to solve it at all quit whatever you are doing, unless its highschool which i doubt?

[SparcASM]

I dont understand this is one of the eassiest things in C++ all you deal with is int main and cout/cin and a couple local variables.What help do you need? you want someone to write the code for you ? or some advice what is the problem? show us the code you tried to write so far and where you are stuck.

If you didnt try to solve it at all quit whatever you are doing, unless its highschool which i doubt?

"all you deal with is int main and cout/cin and a couple local variables."

 

You wouldn't say that if you actually learned C++

[Nineshadow]

"all you deal with is int main and cout/cin and a couple local variables."

You wouldn't say that if you actually learned C++

We have programming classes at high school and we learned c++.However, we mainly do algorithmic. That's very interesting and quite challenging, depending on the problem. Still, the problem of the OP is really easy. It's just a loop, user input and a mathematical formula.

[kbenton00]

int main(int argc, const char * argv[]) {        float usedGallons = 0.0f;    int start = 0, end = 0;    int d = 0;    float m = 0.0f;        while(true)    {        std::cout << "Used gallons";        std::cin >> usedGallons;        if(usedGallons == -1)            break;        std::cout << "Start mileage:";        std::cin >> start;        std::cout << "End mileage:";        std::cin >> end;        d = end - start;        m = d / usedGallons;        std::cout << "Result: " << m << std::endl;    }        return 0;}

I wrote it fast and didn't test it but it should work.

Probably want to throw a quick check in there to make sure that end is greater than start [emoji3]