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Math people: Display Question

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-snip-

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I will make a sketch, give me like a few minutes :P

Here you go: http://linustechtips.com/main/topic/329834-math-people-if-i-have-6x-215-169-monitors-aranged-in-a-2vx3h-ignoring-bezels-what-would-be-the-new-screen-size-h-w-d/#entry4477826

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(21X3)+(2x9) = width 81 inches

21 = height

 

there is no D  :ph34r:

O.o not sure I understand this. the D is the 21.5" that is how you normally measure a screen.

 

I will make a sketch, give me like a few minutes :P

Cool! I am at work right now, shouldn't even be doing this xD

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(21X3)+(2x9) = width 81 inches

21 = height

 

there is no D  :ph34r:

No Diagonal?

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O.o not sure I understand this. the D is the 21.5" that is how you normally measure a screen.

 

Cool! I am at work right now, shouldn't even be doing this xD

whoops. did a mistake.. even my edit is wrong......

~New~  BoomBerryPi project !  ~New~


new build log : http://linustechtips.com/main/topic/533392-build-log-the-scrap-simulator-x/?p=7078757 (5 screen flight sim for 620$ CAD)LTT Web Challenge is back ! go here  :  http://linustechtips.com/main/topic/448184-ltt-web-challenge-3-v21/#entry601004

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No Diagonal?

nvm I misread

~New~  BoomBerryPi project !  ~New~


new build log : http://linustechtips.com/main/topic/533392-build-log-the-scrap-simulator-x/?p=7078757 (5 screen flight sim for 620$ CAD)LTT Web Challenge is back ! go here  :  http://linustechtips.com/main/topic/448184-ltt-web-challenge-3-v21/#entry601004

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37.48^2 = 1404.75

21.08^2 = 444.37

1404.75+444.37 = 1849

sqrt 1849 = 43"?

Sorry, I fucked up. I accidentally multiplied width by 2 rather than 3. The width should be 56.22". Giving a diagonal of about 60". See original post, since amended.
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Here you go, kinda late but a sketch:

5GUFm8A.png

 

@Tim Drake you wanna know? :D

"We're all in this together, might as well be friends" Tom, Toonami.

 

mini eLiXiVy: my open source 65% mechanical PCB, a build log, PCB anatomy and discussing open source licenses: https://linustechtips.com/topic/1366493-elixivy-a-65-mechanical-keyboard-build-log-pcb-anatomy-and-how-i-open-sourced-this-project/

 

mini_cardboard: a 4% keyboard build log and how keyboards work: https://linustechtips.com/topic/1328547-mini_cardboard-a-4-keyboard-build-log-and-how-keyboards-work/

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6x 21.5" 16:9  2Vx3H

 

1 monitor is 18.74" wide by 10.54" high.

 

Therefore 

2 x 10.54" = 21.08"3 x 18.74" = 56.22"

So your rectangle of monitors would be 21" high and 56" wide. It would have a diagonal size of:

a^2 + b^2 = c^2c = root(21.08^2 + 56.22^2)c = 60.04"

EDIT: (20.08", 56.22". 60.04")

EDIT: just realized I screwed up one number, answer corrected.

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Not sure if you saw my correction to my post, so I'm going to post in this again. 

 

If you're interested in learning the formula to calculate width and height given diagonal and a ratio, here is a good post on it: http://math.stackexchange.com/questions/63681/calculate-width-and-height-of-a-rectangle-given-its-diagonal-and-ratio

15" MBP TB

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