Need Help with MATHS :(

[werto165]

Ok, so I'm trying to integrate 2^x and it's not going too well. 

 

I know how to differentiate 2^x:

 

y=2^x

 

ln|y| = x ln|2| 

 

d/dx[ln|y|] = d/dx[x ln|2|] 

 

(1/y)*dy/dx = ln|2| 

 

dy/dx = y * ln|2| 

 

dy/dx = 2^x * ln|2|

 

 

So from here how do it work it backwards? 

 

Image if it's easier to follow. 

 

 

[ReadyToGame]

What the fudge kind of math is this? never seen it like that before

[the jolly roger]

do your own homework you lazy

[werto165]

What the fudge kind of math is this? never seen it like that before

calculus, extremely useful with plenty of applications. 

[ReadyToGame]

calculus, extremely useful with plenty of applications. 

Ah, I cannot help you there.

[Vavetti]

Wasn't that 2^x/ln(2)+c?

Not so sure anymore it has been a while.

[SuperPug]

http://www.wolframalpha.com/input/?i=integrate+2^x

[colonel_mortis]

If you do it by the "best guess" method, you can try 2^x. When you differentiate that, you get 2^xln2. That means that you need to divide by ln2 to get back to your original answer.

Therefore, the correct answer is 2^x/ln2+C

[T.Vengeance]

If you do it by the "best guess" method, you can try 2^x. When you differentiate that, you get 2^xln2. That means that you need to divide by ln2 to get back to your original answer.

Therefore, the correct answer is 2^x/ln2+C

^This. If you wanna show  your work though:

[werto165]

Wasn't that 2^x/ln(2)+c?

Not so sure anymore it has been a while.

 

If you do it by the "best guess" method, you can try 2^x. When you differentiate that, you get 2^xln2. That means that you need to divide by ln2 to get back to your original answer.

Therefore, the correct answer is 2^x/ln2+C

I worked it out in the end. You just have to think of 2^x  in terms of exponential and use substitution , aanyway it's probably easier just to take a pic of my working. 

 

https://docs.google.com/file/d/0B-6QNewcQomZczZOTHdHaVJtWWM/edit?usp=docslist_api

[werto165]

 

^This. If you wanna show  your work though:

 

@T.Vengeance is that done on a  surface tablet or something similar?