if command

[Liam mallka]

I thought that the answer here is always because -8 and 7 arent 0 but its actually false, any ideas why?

 

[Sauron]

& is a bitwise AND operator. Opening the calculator reveals that -8 is represented as

1111 1111 1111 1000

in a 16bit integer

 

whereas 7 is

0000 0000 0000 0111

 

and guess what,

 

1111111111111000 & 0000000000000111 == 0000000000000000 == FALSE

 

[Kilrah]

The above is how & works, you likely intended to use && instead.

[TheBean]

the & operation first compares the 2 numbers and outputs true or false. since -8 and 7 are not the same, "-8 & 7" returns false. so it goes into the else statement.

[Kilrah]

9 minutes ago, The_Vaccine said:

the & operation first compares the 2 numbers and outputs true or false. since -8 and 7 are not the same, "-8 & 7" returns false. so it goes into the else statement.

Why do you feel you need to post a completely wrong explanation when @Saurongave an extremely detailed and correct one?

[TheBean]

16 minutes ago, Kilrah said:

Why do you feel you need to post a completely wrong explanation when @Saurongave an extremely detailed and correct one?

what is wrong about what I said?

[Kilrah]

  

8 minutes ago, The_Vaccine said:

what is wrong about what I said?

 

35 minutes ago, The_Vaccine said:

since -8 and 7 are not the same, "-8 & 7" returns false

 

This. If any of the bits were 1 in both numbers the operation would return true even if the numbers are different. Read Sauron's post.

[Eigenvektor]

13 hours ago, The_Vaccine said:

what is wrong about what I said?

You said "the & operation first compares the 2 numbers" which is incorrect. & is a binary operator. It does not compare anything. It performs a binary "and" operation, which results in a "new" number. This number is then evaluated by the if statement. Any number != 0 is true.