Can you solve?

[ibuildpcswsocks]

2uv^2/uv(2u^-4v^-3)^-4

 

Solve it and it and get a cookie

[Mohenjo]

at least 7 

[vanished]

What do you mean "solve"?  There are two variables, correct?  Do you want one in terms of the other, and in that case which one?

 

Actually, just noticed there isn't even an = sign... WHAT DO YOU WANT FROM US!?

[baxtmann]

 -u2v2 - 2uv2 + 2u + 4v 

  ——————————————————————

            uv          

[Janne]

What do you mean "solve"?  There are two variables, correct?  Do you want one in terms of the other, and in that case which one?

 

Actually, just noticed there isn't even an = sign... WHAT DO YOU WANT FROM US!?

probably means simplify

 

i'm shit at these

[Jykos]

What do you mean "solve"? There are two variables, correct? Do you want one in terms of the other, and in that case which one?

Actually, just noticed there isn't even an = sign... WHAT DO YOU WANT FROM US!?

I believe he means simplify.

[Guest]

Whatever this thing says 

http://www.tiger-algebra.com/drill/2u~-4$v~4$2uv~-4/(uv~-3)~2/

that is my answer

[vanished]

probably means simplify

 

i'm shit at these

oh... then if I read that right,

32vu^(16/v^3)

[andrew.f]

2uv^2/uv(2u^-4v^-3)^-4

 

Solve it and it and get a cookie

 

uv-3 I think

[baxtmann]

Wait.

 

      u¹⁶v¹⁵
——————
        8

 

There we go. That should be it. 

[vanished]

2uv^2/uv(2u^-4v^-3)^-4

 

Solve it and it and get a cookie

K srsly can you write it out more clearly?  Or pick an answer if someone's got it  :rolleyes:

[ibuildpcswsocks]

Whatever this thing says 

http://www.tiger-algebra.com/drill/2u~-4$v~4$2uv~-4/(uv~-3)~2/

that is my answer

you get a cookie fine sir.

[techswede]

To all you that could solve that

The world needs people like you.

 

Because i'm not fucking doing it

[Guest]

you get a cookie fine sir.

[vanished]

you get a cookie fine sir.

so... 

that:   was not what your original post represents?

 

(whoops, missed a negative, but still WHAT WAS IT?)

[Philosobyte]

If this is what you meant: 

_______2uv²_____              

uv ( 2 * u^-4 * v^-3 )^-4

 

_______2v_____                   Cancel the u and the v

( 2 * u^-4 * v^-3 )^-4

 

 

2v * ( 2 * u^-4 * v^-3 )⁴                 Bring the denominator up to get rid of the negative

 

 

2v * (16 * u^-16 * v^-12)             Distribute the exponent

 

 

32 u^-16 v^-11                                Distribute. 

 

 

Did I make any mistakes?

[ben dover kid]

fked up again. i was right at beginning. its 32v. op u better have the answer for this also. 

[sgtcool]

JESUS IS THE ANSWER

[ben dover kid]

If this is what you meant: 

_______2uv²_____              

uv ( 2 * u^-4 * v^-3 )^-4

 

_______2v_____                   Cancel the u and the v

( 2 * u^-4 * v^-3 )^-4

 

 

2v * ( 2 * u^-4 * v^-3 )⁴                 Bring the denominator up to get rid of the negative

 

 

2v * (16 * u^-16 * v^-12)             Distribute the exponent

 

 

32 u^-16 v^-11                                Distribute. 

 

 

Did I make any mistakes?

well i got answer: 32v. i can show u how the heck i did it but.. 

[ben dover kid]

JESUS IS THE ANSWER

bible thumper!

[ben dover kid]

hey op u made the original expression too unclear aswell. 

 

this what you meant:

 

2uv^2 / uv{  [ 2u^(-4) ] x [ v^(-3) ]  }^(-4)

 

others rendered it differently, but thats how u wrote it

[Philosobyte]

well i got answer: 32v. i can show u how the heck i did it but.. 

Please do so. 

[ben dover kid]

sorry for the white blank spots. i had to cut it down so it would be under 2mb. if there is something unclear or u think i did something wrong, let me know 

Please do so.

[Philosobyte]

sorry for the white blank spots. i had to cut it down so it would be under 2mb. if there is something unclear or u think i did something wrong, let me know 

Thanks for sharing. I think you made a mistake. In step 2, you used the theorem you boxed in,  y/x + z/x = (y + z)/x. However, this is only used with addition/subtraction, and in this case numbers aren't added, but multiplied. For multiplication it would be y/x * z/x = yz/(x²)

[ben dover kid]

Thanks for sharing. I think you made a mistake. In step 2, you used the theorem you boxed in,  y/x + z/x = (y + z)/x. However, this is only used with addition/subtraction, and in this case numbers aren't added, but multiplied. For multiplication it would be y/x * z/x = yz/(x²)

ofc i made some stupid mistake like that. i knew i did something wrong lol. to my defense, it was like 1am or something. im gonna do that again but not now i just woke up. =)