Precalc help

[Oberon.Smite]

Welp sorry for posting another problem but I have a quiz tomorrow and if I don't get this homework then i'm screwed.

 

 

Please help, I need to find the exact value.

[Enderman]

tan^-1 cancels out tan...

so the answer is just 5pi/6

[Oberon.Smite]

tan^-1 cancels out tan...

so the answer is just 5pi/6

5pi/6 isn't in the right quadrant. I figured it out to there, but the thing is that tan^-1 is only in quadrants 1 and 4.

[Oberon.Smite]

tan^-1 cancels out tan...

so the answer is just 5pi/6

I get the shortcut but still tho why does it get a pass on being in the second quadrant.

[Enderman]

5pi/6 isn't in the right quadrant. I figured it out to there, but the thing is that tan^-1 is only in quadrants 1 and 4.

you can just draw a line straight through and put that angle in the 4th quadrant

https://ca.answers.yahoo.com/question/index?qid=20111022043932AAjVcIL

so basically just take pi and subtract that

so you get -pi/6

[Oberon.Smite]

you can just draw a line straight through and put that angle in the 4th quadrant

https://ca.answers.yahoo.com/question/index?qid=20111022043932AAjVcIL

so basically just take pi and subtract that

so you get -pi/6

THANK YOU M8 I FINALLY UNDERSTAND IT. All you have to do is subtract pi radians or add pi radians to get it into the right quadrant.

 

THANK YOU