Can Someone Help Me?

[byalexandr]

I'm in college algebra, a dual credit class at my high school. We are reviewing stuff from Algebra II and I cannot for the life of my figure some of this stuff out, it's just not coming back to me. Here is one of the problems I am stuck on:

 

(32x^10y^5)^(3/5)

 

That is, 32 times x to the power of 10 times y to the power of five, all to the power of 3/5. I am supposed to simplify the problem but I'm just not sure what I'm supposed to start with. Can someone guide me through this? Thanks!

 

Also stuff like (x+y)^2 - 25, I don't know why but I just can't get any of these problems started, but once I get them started usually it's really easy to finish them.

[byalexandr]

I know I'm asking a lot but I really need help.

[cortexcortex]

8x^6y^5

[byalexandr]

8x^6y^5

Well I asked for help not just an answer. Could you please explain how you got that?

 

Edit: Wait, how does that make sense? That's like three different powers?

[werto165]

Well I asked for help not just an answer. Could you please explain how you got that?

n/5 is the fifth root, 3/n is just cubed. Root it first AFAIK, haven't really looked at it too hard. 

[Philcat101]

I'm in college algebra, a dual credit class at my high school. We are reviewing stuff from Algebra II and I cannot for the life of my figure some of this stuff out, it's just not coming back to me. Here is one of the problems I am stuck on:

 

(32x^10y^5)^(3/5)

 

That is, 32 times x to the power of 10 times y to the power of five, all to the power of 3/5. I am supposed to simplify the problem but I'm just not sure what I'm supposed to start with. Can someone guide me through this? Thanks!

 

Also stuff like (x+y)^2 - 25, I don't know why but I just can't get any of these problems started, but once I get them started usually it's really easy to finish them.

Distribute the 3/5 power in the parenthesis.

[byalexandr]

Okay, is this right?

 

After distributing the fifth root into the parentheses I get this:

 

(2x^2y)^3

 

Then distribute the cube into the parentheses and get this:

 

8x^6y^3

 

Is that right?

 

@

@werto165

[byalexandr]

What happens if the the equation has a negative root to it? Like it's -2/3 instead of 2/3, but there are no fractions for it to flip. Would it be 1 over whatever is in the parentheses?

[Philcat101]

Okay, is this right?

 

After distributing the fifth root into the parentheses I get this:

 

(2x^2y)^3

 

Then distribute the cube into the parentheses and get this:

 

8x^6y^3

 

Is that right?

 

@

@werto165

Yes. Lol im 14 and i helped a college student

[byalexandr]

Yes. Lol im 14 and i helped a college student

THANK YOU. This is Algebra review, it gets a lot harder than this, I can't even remember basic concepts.

 

I'm so screwed.

[Philcat101]

What happens if the the equation has a negative root to it? Like it's -2/3 instead of 2/3, but there are no fractions for it to flip. Would it be 1 over whatever is in the parentheses?

it flips everything under a fraction

so 1^-1 would be 1/1^1

2^-3 would be 1/2^3

[byalexandr]

it flips everything under a fraction

so 1^-1 would be 1/1^1

2^-3 would be 1/2^3

Thanks so much, makes so much more sense now.

[werto165]

Thanks so much, makes so much more sense now.

I thought the answer would be 8x^6y

 

as x^a * x^b = x^a+b I think 

[byalexandr]

I thought the answer would be 8x^6y

 

as x^a * x^b = x^a+b I think 

But there are two different variables, x and y.