How would I do this? C#

[werto165]

            //Ask user for Complex Number + reads it             Console.WriteLine("Please Enter your Complex Number");            string imaginaryNo = Console.ReadLine();            //Converts number into char array            char[] imaginaryNoArray = imaginaryNo.ToArray();            //Goes through each char in array            for (int i = 0; i < imaginaryNo.Length; i++)            {                //finds the index of the imaginary part of the number                if (imaginaryNoArray[i] == 'i')                {                    //Only works for single digit imaginary numbers                     char Imaginary = imaginaryNoArray[(i - 1)];                    Console.WriteLine("The Imaginary Part of your number is {0}" ,Imaginary);                 }            }#region                 //Ignore this            //var c1 = new Complex(1,2);             //Console.WriteLine(c1.ToString()); #endregion        

I'm trying get an imaginary part of a number this example works only for single digit Imaginary numbers:

e.g. 

10 + 5i ---> result being = The Imaginary Part of your number is 5 

 

10+ 63i ---> result being = The Imaginary Part of your number is 3 (should be 63) 

 

How would I implement it to work for any number of digits? 

 

Also I can't seem to get Imaginary to work outside the if loop(just says doesn't exist within the current context.

[Satlen]

Well since it will always end in "i" you can start at the i and then loop backwards through the input until you hit a non-number character.

[Guest]

You're almost there. Instead of hard-coding the i - 1 to get the index of the number, call a function that walks backwards from the index of "i", gathering all the preceding integers into a string to print.

[RockiLocky]

~snip~

If you can wait till 5pm GMT+1 (is in 10hours) I can give you a code that will solve your propblem with comments if xou want

[werto165]

You're almost there. Instead of hard-coding the i - 1 to get the index of the number, call a function that walks backwards from the index of "i", gathering all the preceding integers into a string to print.

Yeah, I finally did it, not exactly the most succinct code ever but, it's better than not working at all.

//empty string to hold the data             string imagString = "";            int imaginaryNoIndex = 1;             //Ask user for Complex Number + reads it             Console.WriteLine("Please Enter your Complex Number");            string imaginaryNo = Console.ReadLine();            //Converts number into char array            char[] imaginaryNoArray = imaginaryNo.ToArray();            //Goes through each char in array backwards            for (int i = imaginaryNo.Length- 1; i > 0; i--)            {                //finds the index of the imaginary part of the number                if (imaginaryNoArray[i] == 'i')                {                    imaginaryNoIndex = i-1;                     Console.WriteLine(imaginaryNoIndex);                }                //Goes through the array backwards until it no longer finds a # value.                while (char.IsNumber(imaginaryNoArray[imaginaryNoIndex]))                {                    imagString = imagString + imaginaryNoArray[imaginaryNoIndex];                    imaginaryNoIndex--;                    break;                }                            }                        char[] imagStringArray = imagString.ToCharArray();            //Reverse the char array.             Array.Reverse(imagStringArray);            //Make a new string from the inversed char array.             string stringReverse = new string(imagStringArray);             Console.WriteLine("Imaginary Number is {0}i", stringReverse);            Console.ReadLine();            }