Maths Question

[Wictorian]

Can someone explain what are we supposed to do here?

[tikker]

Not without a lot more context of what it is you are trying to solve or do. The right hand term reminds me of the binomial coefficient.

[Chris Pratt]

Yeah, that's the notation for binomial coefficients. The term on the left side is actually the central binomial coefficient, though it uses "N" instead of the more traditional "n". My math is a little rusty to know exactly what it's trying to make you do here, though.

[Wictorian]

8 hours ago, tikker said:

Not without a lot more context of what it is you are trying to solve or do. The right hand term reminds me of the binomial coefficient.

 

3 hours ago, Chris Pratt said:

Yeah, that's the notation for binomial coefficients. The term on the left side is actually the central binomial coefficient, though it uses "N" instead of the more traditional "n". My math is a little rusty to know exactly what it's trying to make you do here, though.

Yes it is the binomial coefficient, my question is what to do when a number/variable is on top of another one as shown in the picture.

[tikker]

1 hour ago, Wictorian said:

 

Yes it is the binomial coefficient, my question is what to do when a number/variable is on top of another one as shown in the picture.

What do you mean "on top of"? Are you referring to 2N? In that case you could just treat 2N as a single entity for now and expand both coefficients as if 2N = x.

 

Still it's guesswork as you haven't told us what you are trying to do. What is the question surrounding this? Solve for N? Simplify? Calculate something else?

[Wictorian]

12 hours ago, tikker said:

What do you mean "on top of"? Are you referring to 2N? In that case you could just treat 2N as a single entity for now and expand both coefficients as if 2N = x.

 

Still it's guesswork as you haven't told us what you are trying to do. What is the question surrounding this? Solve for N? Simplify? Calculate something else?

I am asking what operation to do when 2N is on top of N. For instance if there was a line in between we would divide 2N by N and it would result in 2.

[tikker]

19 minutes ago, Wictorian said:

I am asking what operation to do when 2N is on top of N. For instance if there was a line in between we would divide 2N by N and it would result in 2.

Well as @Chris Pratt says it seems to be the notation for the central binomial coefficient, which has an expanded form you can look up on e.g. Wikipedia. Same for the right hand side, but just the regular binomial coefficient.

[Wictorian]

9 minutes ago, tikker said:

Well as @Chris Pratt says it seems to be the notation for the central binomial coefficient, which has an expanded form you can look up on e.g. Wikipedia. Same for the right hand side, but just the regular binomial coefficient.

So there is not a default operation? For instance this doesn't mean anything:
 

(4)

(3)

 

or 

 

(x)

(y)

[tikker]

7 minutes ago, Wictorian said:

So there is not a default operation? For instance this doesn't mean anything:
 

(4)

(3)

 

or 

 

(x)

(y)

Without context, no. I only thought of the binomial coefficient because that often uses n and k. If you'd shown us generic vectors with N, x and y I would've assumed them to be, well, two random vectors. The question therefore again becomes, what is the surrounding question / problem? Is there even one?

 

If it is binomial stuff, then you can find the expansions e.g. here:

https://en.wikipedia.org/wiki/Central_binomial_coefficient

https://en.wikipedia.org/wiki/Binomial_coefficient