Help with Java Assignment

[Sdot]

I have a  .java file that I have written so far. There is one last requirement that I have to create. I am having difficulty creating it so I am here looking for assistance.

 

My code reads in numbers, these numbers are then put into an array named values. I have a for loop, if the number entered is bigger than any of the previous "values", it becomes the largest value. I named that variable "largest".

Can anyone help me keep track of how many times the largest value was typed? I'm guessing I would use another for loop.

 

Please help, thanks guys. I have attached my code to this post.

Assignment.java

[Enderman]

Yes, after the first loop runs you will need to make a second loop that goes through the list again and counts the times that "largest" shows up.

[JoostinOnline]

It's been a long time since I've used Java, but I think this will work.  Replace:

 

if (values[i] > largest)
{
	largest = values[i];
	occurance++;
}

with

if (values[i] > largest)
{
	largest = values[i];
	occurance = 1;
} else if (values[i] == largest) {
	occurance++;
}

 

[Sdot]

5 minutes ago, JoostinOnline said:

It's been a long time since I've used Java, but I think this will work.  Replace:

 

if (values[i] > largest)
{
	largest = values[i];
	occurance++;
}

with

if (values[i] > largest)
{
	largest = values[i];
	occurance = 1;
} else if (values[i] == largest) {
	occurance++;
}

 

Works perfectly

Thanks guys, You the man Joostin

 

[JoostinOnline]

2 minutes ago, Sdot said:

Works perfectly

Thanks guys, You the man Joostin

 

Since it's homework I should explain why it works.  A higher number will always reset the value to 1, because it means it's never been input before.  Every time it finds it after that, it will increase occurance (which is misspelled, btw) by one.

 

The "else" is important.  If it didn't exist, then occurance would always be at least 2.

[Sdot]

2 minutes ago, JoostinOnline said:

Since it's homework I should explain why it works.  A higher number will always reset the value to 1, because it means it's never been input before.  Every time it finds it after that, it will increase occurance (which is misspelled, btw) by one.

 

The "else" is important.  If it didn't exist, then occurance would always be at least 2.

Occurrence, got it lol

I'm testing it now, I put in 10 10 10 then q to stop it and it says the largest number has ocured 2 times. I am trying to figure out why. Should be 3.

[JoostinOnline]

3 minutes ago, Sdot said:

Occurrence, got it lol

I'm testing it now, I put in 10 10 10 then q to stop it and it says the largest number has ocured 2 times. I am trying to figure out why. Should be 3.

Like I said, my Java is rusty, but I think you're skipping the first entry.  Try entering "3,10,10,10,Q" and see if it says 3 times.

[Sdot]

6 minutes ago, JoostinOnline said:

Like I said, my Java is rusty, but I think you're skipping the first entry.  Try entering "3,10,10,10,Q" and see if it says 3 times.

Your rusty java > my little to no java knowledge lol. Yes, it worked

 

Please enter values, Q to quit:
3
10
10
10
q
10 <== largest value
The array has been increased 4 times.
Largest number has occurred 3 times.
Press any key to continue . . .

 

OH, I think I understand why it did that. The if statement if (values > largest) cannot run because it is the first integer. There is nothing for it to be greater than. Basically it doesn't start counting yet.

 

[JoostinOnline]

It's because you start i at 1, completely skipping values[0].  Change

for (int i = 1; i < currentSize; i++)

to

for (int i = 0; i < currentSize; i++)

 

[Sdot]

1 minute ago, JoostinOnline said:

It's because you start i at 1, completely skipping values[0].  Change

for (int i = 1; i < currentSize; i++)

to

for (int i = 0; i < currentSize; i++)

 

Correct, that solved it. Thank you so much Joostin! Thank you, mostly for helping me to understand it instead of just saying "plug this in, it should work". This work is cumulative so this information will help me at the end of the semester. We have to write a big program for the final exam that will utilize everything we have learned.

[JoostinOnline]

Just a tip: You can actually skip that entire last for loop and replace it with a single line, since you already have the largest value stored in largest.

[Sdot]

3 minutes ago, JoostinOnline said:

Just a tip: You can actually skip that entire last for loop and replace it with a single line, since you already have the largest value stored in largest.

Good eye