Basic Python Book

[cheshgoalie21]

I am taking a basic programming class and we are starting to use python and using the book "starting out with Python Third Edition". At the end of each chapter we have to do an exercise. This chapter focuses a lot on if-else and if-elif-else statements so I need to use that. The exercise I am doing goes like this:

 

Write a program that asks the user to enter the weight of a package and then displays the shipping charges. The charges are as follows: 2 pounds or less is $1.50 per pound, Over 2 pounds but not more than 6 pounds is $3.00 per pound, Over 6 pounds but not more than 10 pounds is $4.00 per pound, and then Over 10 pounds is $4.75 per pound.

 

x = float(input('What is the weight of the package?'))
if x <= 2:
    int(input(x*1.50))
elif x >2<=6:
    int(input(x*3.00))
elif x >6<=10:
    int(input(x*4.00))
else:
    int(input(x*4.75))

 

The program works until I input a number that is great than 6 in, it just multiplies it as if it was part of the $3 category.

Any help would be greatly appreciated thanks!

[mkylem]

I'm not too versed in Python, but try "elif 2<x<=6". x is greater than 2 when you're entering something greater than six and 2 is always less than 6 so it will default to the $3 category

[vectorx5000]

5 minutes ago, mkylem said:

I'm not too versed in Python, but try "elif 2<x<=6". x is greater than 2 when you're entering something greater than six and 2 is always less than 6 so it will default to the $3 category

Yeah, try that. At least in mathe, the < and > signs always go the same direction in an inequality. It should 

EDIT: In the second elif, it should be 6<x<=10 NOT x>6<=10. yours doesn't actually mean anything.

[cheshgoalie21]

5 minutes ago, mkylem said:

I'm not too versed in Python, but try "elif 2<x<=6". x is greater than 2 when you're entering something greater than six and 2 is always less than 6 so it will default to the $3 category

 

2 minutes ago, vectorx5000 said:

Yeah, try that. At least in mathe, the < and > signs always go the same direction in an inequality.

Below is the updated code and yes it worked thank you very much for the help. Its funny how the littlest things can throw everything off but I guess in the world of computing this just shows how precise everything must be. 

 

x = float(input('What is the weight of the package?'))
if x <= 2:
    int(input(x*1.50))
elif 2<x<=6:
    int(input(x*3.00))
elif 6<x<=10:
    int(input(x*4.00))
else:
    int(input(x*4.75))

[vectorx5000]

Just now, cheshgoalie21 said:

 

Below is the updated code and yes it worked thank you very much for the help. Its funny how the littlest things can throw everything off but I guess in the world of computing this just shows how precise everything must be. 

 

x = float(input('What is the weight of the package?'))
if x <= 2:
    int(input(x*1.50))
elif 2<x<=6:
    int(input(x*3.00))
elif 6<x<=10:
    int(input(x*4.00))
else:
    int(input(x*4.75))

Yes it does have to be precise, but your inequality didn't make any mathematical sense.

[vectorx5000]

14 minutes ago, cheshgoalie21 said:

I am taking a basic programming class and we are starting to use python and using the book "starting out with Python Third Edition". At the end of each chapter we have to do an exercise. This chapter focuses a lot on if-else and if-elif-else statements so I need to use that. The exercise I am doing goes like this:

 

Write a program that asks the user to enter the weight of a package and then displays the shipping charges. The charges are as follows: 2 pounds or less is $1.50 per pound, Over 2 pounds but not more than 6 pounds is $3.00 per pound, Over 6 pounds but not more than 10 pounds is $4.00 per pound, and then Over 10 pounds is $4.75 per pound.

 

x = float(input('What is the weight of the package?'))
if x <= 2:
    int(input(x*1.50))
elif x >2<=6:
    int(input(x*3.00))
elif x >6<=10:
    int(input(x*4.00))
else:
    int(input(x*4.75))

 

The program works until I input a number that is great than 6 in, it just multiplies it as if it was part of the $3 category.

Any help would be greatly appreciated thanks!

As a general rule, inequalities should be "x<y<z" or "x>y>z". (adding the or equal to as necessary.)

[cheshgoalie21]

1 minute ago, vectorx5000 said:

As a general rule, inequalities should be "x<y<z" or "x>y>z". (adding the or equal to as necessary.)

For some reason I thought of x >6<=10 being like if x is greater than 6 but less than or equal to 10 then it should do this line of code-> int(input(x*4.00))

 

I wasn't thinking straight or really thinking logically, like I said I'm new to this but thank you for the advice!