Switch question

[mikestechs]

Hello guys, i just want to ask if there is any way to figure out this...
If i will have 

int a;

System.out.println("Type number 1 or 2 ");

a = sc.nextInt();

 

switch(a)

{

case 1:

something...

break;

 

case 2:

something...

break;

default:

something...

 

break;

}

 it doesnt metter what is inside "cases and default" but what i need to know how can i figure out the thing that when someone stupid (our teacher everytime try to crash our programm) will write 0,1 or something under a <0 ?  is there any possible wait to "fix it" 

I'm thinking about something like whe user types something < 0 the programm will "type" System.out.println("You need to type nuber 1 or 2")

[madknight3]

First, please use code tags when posting code on the forum.

 

To answer your question, if you're not allowed to assume that the input is always correct, then you can use a try/catch to handle what happens if a = sc.nextInt(); throws an exception.

[mikestechs]

5 minutes ago, madknight3 said:

First, please use code tags when posting code on the forum.

 

To answer your question, if you're not allowed to assume that the input is always correct, then you can use a try/catch to handle what happens if a = sc.nextInt(); throws an exception.

First, sorry for that. 

And thank you so much! really good idea

 

[YellowRubberDucky]

You could also do a int.tryparse, then you can badger the user for an integer.

[madknight3]

45 minutes ago, YellowRubberDucky said:

You could also do a int.tryparse, then you can badger the user for an integer.

As I mainly use C# this was my first thought too, but I looked it up and I don't think Java has that.

[YellowRubberDucky]

Correct java does not have that function. You could always create a tryparse method but you would be using the try and catch block within it. If you are going to need to parse multiple strings I would create the method. If you just need it for one string I would use the try/catch block.

[alex_read]

Java has

Integer.parseInt(stringValueHere);