Convert char array to int (c++)

[MisterWhite]

i know i can convert this:

char myChar[] = "125697"

to ant integer

but will something like this work?:

char myChar [] = "125    "

[TacticalCuda]

Im new to C++ but i think it may work due to logic.

[Xenift]

https://www.google.com.sg/search?q=char+values&espv=2&biw=1920&bih=979&source=lnms&tbm=isch&sa=X&ved=0ahUKEwie8MavrovKAhXCto4KHVFSAJ0Q_AUIBigB#imgrc=HsBLVbFjwLQlQM%3A

 

I don't think spaces have any values under the table.

 

Might just work fine.

[manon_gfx]

What exactly do you mean by convert?

Like turn the string "125     " into a number?
Or reinterpret the data as integers?
 

Converting to a number can simply be done using atoi: 

int value = atoi(cString);

To reinterpret cast you can do one of the following:

const int* array = (int*)cString;

It would be nice if you could explain what your question is a bit more!

[Nineshadow]

 

i know i can convert this:

char myChar[] = "125697"

to ant integer

but will something like this work?:

char myChar [] = "125    "

For the first example, do you mean getting an integer with the value 125697 , from a character array holding "125697"?

 

Since C++11 , we've had std::stoi() , which takes as a parameter an std::string. If you still want to use cstrings , then there's atoi().

 

Or you can make your own function :

// c - pointer to a null-terminated arrayint atoi(char *c){int i = 0,s=0;//while we are still in the memory assigned to the arraywhile(c[i]!='\0'){//If the character we are currently  looking at is a numberif(c[i] >= 48 && c[i] <= 57) s = s*10 + c[i] - 48;//Next character in the arrayi++;}//Return the numberreturn s;}

[SteveGrabowski0]

nm 

[MisterWhite]

 

 

yeah, i've learned about atoi(), my question was that if there are spaces after the number, will it convert properly, and it does, so it is answered