Simple java number question.

[Justin Meyer]

Ok so im in a class at my school that teaches java (AP Computer Science) and right now were making a program that prints a random phone number. However the thing is that the first 3 digits cannot have 8 or 9 in them and the middle 3 numbers cannot be bigger than 742. Basically i need to know how to exclude a number from something such as this:

 

num1 = generator.nextInt(random # here but cannot include 8 or 9) +1;

 

the string above needs to be able to include a 0 so it cannot just stop at 7. So basically i just need to know how to exclude certain numbers if someone could help me out i would really appreciate it.

[ALwin]

Hint:

If generated number X = 8 or 9 then discard value and regenerate number X

If generated numbers X+Y+Z < 742 then accept value, or generate number within a certain range

 

EDIT: this is just one method, there are other possible solutions

[pureGold]

Math.random() * 7

This line of code will give you a random integer between 0 and 7, but you will have to figure out how to cast the outputted double value into a integer. (Not trying to be mean, but you have to learn).

 

For the second part, it is basically the same thing, but with a range of 0 - 742, so try and figure it out.