Need help with math!

[xnoobftw]

The question states that compute the range of the following real valued functions and determine if it is onto

 

F(x)=ln(x^2) ; x doesnt equal to 0

 

How does one prove this crap? LOL

I dont understand this particular question only D:

 

Thank you in advance for your help!  

[Vitalius]

The question states that compute the range of the following real valued functions and determine if it is onto

 

F(x)=ln(x^2) ; x doesnt equal to 0

 

How does one prove this crap? LOL

I dont understand this particular question only D:

 

Thank you in advance for your help!

>The question states that compute the range of the following real valued functions and determine if it is onto

I think you didn't finish your sentence. I'm confused.

[xnoobftw]

>The question states that compute the range of the following real valued functions and determine if it is onto

I think you didn't finish your sentence. I'm confused.

Basically the question asks us to find the range of the real valued function and determine if it is an onto function!  

[dragosudeki]

Well x can only go from 0<x<infinity. If I recall correctly, ln(x) can go from negative infinity to infinity as well in terms of real numbers. Since the set of real numbers ranges from negative infinity to positive infinity, it should be onto. Though, you might need something more formal than that.

[T.Vengeance]

You can prove it by switching the ln function to an e^x function. By doing that, you switch the range of ln(x^2) to the domain of e^(x^2). Since the domain of e^(x^2)  is all real numbers, therefore the range of ln(x^2) is all real numbers.

[rmac52]

Not sure what the actual question is but the function y=ln(x^2) can not equal 0.  So the function does NOT equal all numbers from -∞ to ∞

[rmac52]

If I could guess I would saw English is not your 1st language.  The function y=ln(x^2) is not continues.  I think that's what you mean but onto.

No offence intended.

[xnoobftw]

Well x can only go from 0<x<infinity. If I recall correctly, ln(x) can go from negative infinity to infinity as well in terms of real numbers. Since the set of real numbers ranges from negative infinity to positive infinity, it should be onto. Though, you might need something more formal than that.

 

 

You can prove it by switching the ln function to an e^x function. By doing that, you switch the range of ln(x^2) to the domain of e^(x^2). Since the domain of e^(x^2)  is all real numbers, therefore the range of ln(x^2) is all real numbers.

 

 

Not sure what the actual question is but the function y=ln(x^2) can not equal 0.  So the function does NOT equal all numbers from -∞ to ∞

 

 

 

Hmmm guys from what i understand an onto function is one that streches out indefinitely when placed on a graph.

(Is that even correct?) 

When i google ln(x^2) it gives me a graph that looks like it isnt an onto function by my definition. 

However the answer key in my book states that the function is an onto one.....

[xnoobftw]

If I could guess I would saw English is not your 1st language.  The function y=ln(x^2) is not continues.  I think that's what you mean but onto.

No offence intended.

Yeap! Mandarin is my first language  

[T.Vengeance]

Hmmm guys from what i understand an onto function is one that streches out indefinitely when placed on a graph.

(Is that even correct?) 

When i google ln(x^2) it gives me a graph that looks like it isnt an onto function by my definition. 

However the answer key in my book states that the function is an onto one.....

Onto function?

 

GG I'm in engineering and this is the first time I've heard of onto functions.

[blackadder]

Isnt ln transcendent, no rational values only reals.

[Delusional Phil]

Hmm ... I have the same kind of homework before ... Only it's harder ... and you have to do it by hand ... And what is " In " ? I barely knew have of the functions of my calculator ... 

[xnoobftw]

Onto function?

 

GG I'm in engineering and this is the first time I've heard of onto functions.

Yeap

 

Isnt ln transcendent, no rational values only reals.

The graph is pretty weird though.... Yes it is!

 

Hmm ... I have the same kind of homework before ... Only it's harder ... and you have to do it by hand ... And what is " In " ? I barely knew have of the functions of my calculator ... 

it's like the function on the calculator? You know log? It is similar to it!

[Delusional Phil]

it's like the function on the calculator? You know log? It is similar to it!

What's Log ? 

[dragosudeki]

Hmmm guys from what i understand an onto function is one that streches out indefinitely when placed on a graph.

(Is that even correct?) 

When i google ln(x^2) it gives me a graph that looks like it isnt an onto function by my definition. 

However the answer key in my book states that the function is an onto one.....

I believe onto means the question is asking if the function produces all Real numbers. Looking at the graph, you can see that all possible values of y are from negative infinity to positive infinity. Slowly, but surely will the values of y reach a very large number. The values of x do not matter.

[Bouzoo]

Does this help?

 

https://www.wolframalpha.com/input/?i=ln%28x%5E2%29

 

Do you use that ln has the base e or 10?