if(y[0]==let)

[ichihgo]

y[] is an array carrying names ex.( John , Sarah )

 

let is a char ex.( J ,S, M)

 

   if(y[0]==let)

    {

        sum=sum+x;

   }

 

 

how to make the condition valid !?  

[Guest]

you cant store whole string in y[0]

 

and if you want to compare strings than use strcmp();

[LorenzArnua]

If you explain more you are trying to do we can help dont know which language it is

 

well let me try

 

are you tring to match first letter of chars maybe?

than in pseudo code

 

for(int i = 0; i<y.length; i++){

  if(y[0]==let){

    sum = sum+x;

  }

}

[ichihgo]

If you explain more you are trying to do we can help dont know which language it is

 

well let me try

 

are you tring to match first letter of chars maybe?

than in pseudo code

 

for(int i = 0; i<y.length; i++){

  if(y[0]==let){

    sum = sum+x;

  }

}

are you tring to match first letter of chars maybe?

 

This and C++

[LorenzArnua]

y[0]==let

it should work fine

[ichihgo]

y[0]==let

it should work fine

 

This what I was missing and why y[0] can't I just use y[0] !?

 

Edit :  NVM got it

[LorenzArnua]

y[0] is the pointer to whole string

just try cout<<y[0]; and see it yourself

 

you want to access first letter of char array so y[0][0]

 

        0123

y[0]  Jack

y[1]  Sarah