So I'm insanely new and fresh to coding with little to no experience at all. can someone help me with C? here's the code so far: #include<stdio.h>#include<conio.h>main() { int x,arr[7][9]={1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31,32,33,34,35,36,37,38,39,40,41,42,43,44,45,46,47,48,49,50,51,52,53,54,55,56,57,58,59,60,61,62,63}; clrscr(); for(x=0;x<63;x++); { printf("\t%d \t%d \t%d \t%d \t%d \t%d \t%d\n",arr[0][0],arr[0][1],arr[0][2],arr[0][3],arr[0][4],arr[0][5],arr[0][6]); printf("\t%d \t%d \t%d \t%d \t%d \t%d \t%d\n",arr[0][13],arr[0][12],arr[0][11],arr[0][10],arr[0][9],arr[0][8],arr[0][7]); printf("\t%d \t%d \t%d \t%d \t%d \t%d \t%d\n",arr[0][14],arr[0][15],arr[0][16],arr[0][17],arr[0][18],arr[0][19],arr[0][20]); printf("\t%d \t%d \t%d \t%d \t%d \t%d \t%d\n",arr[0][27],arr[0][26],arr[0][25],arr[0][24],arr[0][23],arr[0][22],arr[0][21]); printf("\t%d \t%d \t%d \t%d \t%d \t%d \t%d\n",arr[0][28],arr[0][29],arr[0][30],arr[0][31],arr[0][32],arr[0][33],arr[0][34]); printf("\t%d \t%d \t%d \t%d \t%d \t%d \t%d\n",arr[0][41],arr[0][40],arr[0][39],arr[0][38],arr[0][37],arr[0][36],arr[0][35]); printf("\t%d \t%d \t%d \t%d \t%d \t%d \t%d\n",arr[0][42],arr[0][43],arr[0][44],arr[0][45],arr[0][46],arr[0][47],arr[0][48]); printf("\t%d \t%d \t%d \t%d \t%d \t%d \t%d\n",arr[0][55],arr[0][54],arr[0][53],arr[0][52],arr[0][51],arr[0][50],arr[0][49]); printf("\t%d \t%d \t%d \t%d \t%d \t%d \t%d\n",arr[0][56],arr[0][57],arr[0][58],arr[0][59],arr[0][60],arr[0][61],arr[0][62]); } getch(); return 0; } Output: I do not completely understand how this code works or fully understand arrays at this point. I get the general idea of arrays, but I just don't know how to properly and effectively code it yet. and I'm also wondering how to get the same output using some for loop statements. and less lines of code. any help would be greatly appreciated! Thanks! p.s. links and other stuff that'll teach me about C would be appreciated as well!

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Help with C.

By protato117
November 13, 2014 in Programming

Go to solution Solved by Art Vandelay, November 16, 2014

I'm tryna make sense out of this code but I can't seem to fully understand it...can you please explain this further? just the printf bit at least...

I think it works out to:

		// % is the modulo operator		if ((x+1)%7 != 0) //(x+1)%7?"\t%d":"\t%d\n" this is a ternary operator, basically if-else on the same line. 0 means false, not 0 means true in a boolean expression, you don't need a comparison.		{			if ((x/7) % 2 == 1) //x/7&1?6-x%7:x%7 another ternary operator. & is the logical AND operation. doing &1 checks the last binary digit, which is 1 if odd, 0 if even.			{				printf("\t%d",(arr)[x/7*7 + 6-x%7]); //x/7 is the row at which the point is. Adding to the variable arr is the same as adding the same number to the index								     //this is because arr is the memory index of the first element of the array, and adding 1 to arr iterates                                                                      //the memory index by 1, pointing to the next index		                                                     //note that iterating the memory pointer by 1 moves you 1*(the size of the data type) in memory			}			else 			{				printf("\t%d",(arr)[x/7*7 + x%7]);			}		}		else		{			if ((x/7) % 2 == 1)			{				printf("\t%d\n",(arr)[x/7*7 + 6-x%7]);			}			else 			{				printf("\t%d\n",(arr)[x/7*7 + x%7]);			}		}	}

Hopefully that helps, and please never use ~~modulo~~ ternary operators in your code. They are very irritating to read.

edit: I said modulo instead of ternary by accident. I don't really proof read.

Posted November 17, 2014

Unless you're doing something like code golf, don't write code like that. Write nice code that is, at least, reasonably easy to read and understand lol

Golfing is fun. I should have prefaced my post with just because you can doesn't mean you always should.

Conditional expressions are useful. Just don't abuse them like I did.

I'd rather write printf("some message ... %s\n", str ? str : "<<null str>>"); than an if block though.

main(i){for(;i<101;i++)printf("Fizz\n\0Fizzz\bBuzz\n\0%d\n"+(!(i%5)^!!(i%3)*3)*6,i);}