Python Help!

[X1XNobleX1X]

 

 

Hello forums,

I'm in need of Python help, this is my code at the moment. 

 

temp = int(input("Temperature:"))

while "42" not in temp:

  temp  = input("Temperature:")

  if temp == 42:

  print("Just right!")

elif temp > 42: 

  print("Too hot!")

elif temp < 42:

  print("Too cold!")

  

 

It mostly does what it has to do without the "while" but the question is asking to repeat "Temperature" if the temperature is either too cold or too hot and the code stops if the temperature is 42. 

Here is the example.

 

Temperature: 12

Too cold!

Temperature: 36

Too cold!

Temperature: 39

Too cold!

Temperature: 46

Too hot!

Temperature: 51

Too hot!

Temperature: 43

Too hot!

Temperature: 42

Just right!

 

 

Thanks for all the help!

 

 

[Manny Calavera]

Did you try to run it?  What error or result you got?

[X1XNobleX1X]

Did you try to run it?  What error or result you got?

This is the error:

Traceback (most recent call last):

  File "program.py", line 3, in <module>

    while "42" not in temp:

TypeError: argument of type 'int' is not iterable

[Manny Calavera]

 

This is the error:

Traceback (most recent call last):

  File "program.py", line 3, in <module>

    while "42" not in temp:

TypeError: argument of type 'int' is not iterable

 

Well, google is your friend. You have to understand errors first.

So just google error last line and figure it out.

 

Why are you searching 42 in temp. Temp is not a list of numbers. Temp IS a number, an integrer. Its the input temperature number.

[bmxtricky5]

Just run a condition to check if temp is = 42 if it is print something. If you want to to keep looping till it hits 42 run a while true statement and if it hits 42 break it. I'm basing this off how I do it in c++ so it might be different in python

Also it its probably getting mad because it looks like your searching for 42 that would be in something like a array and since its just a plain integer it gets mad