python list question

[FreQUENCY]

Hello. I want to make a calculation with the lists items. If the item[x] is a 2 digit number like 11 make a sum of them and replace item[X] with the calculation,which in case is 2(1+1).Essentially divide the item to 2 INT numbers and sum them replacing the list item with the result. Any ideas how?

 

[Hugs12343]

>>> n = 123456789
>>> [(n//(10**i))%10 for i in range(math.ceil(math.log(n, 10))-1, -1, -1)]

//Output will be


[1, 2, 3, 4, 5, 6, 7, 8, 9]

This is a way of doing it without stringing the list/variable first.

[FreQUENCY]

@Hugs12343 I meant that if a list has an item "12",then this will be replaced with the sum of these 2 digits. So it will be 3

[Hugs12343]

1 minute ago, FreQUENCY said:

@Hugs12343 I meant that if a list has an item "12",then this will be replaced with the sum of these 2 digits. So it will be 3

So what I posted before will get you the separated string.

You just need to convert it back to an int 

 

int(x)

then add the items in the list together

 

sum(listx)

 

[CPBuchholz]

You could convert them to a string and split out each character then convert each character to an int and sum them or you can do it mathmatically using the modulus operator '%'. The first way would probably be easier to do... lol. Also, if the sum is still greater than 9 then just do it again if that's the required result.

[FreQUENCY]

@CPBuchholz @Hugs12343 

 

def digit_sum(LIST):
    for i in range(len(LIST)):
      value = str(LIST[i])
      digits = [int(x) for x in value]
      credit_card.append(sum(digits))

 

 

Done ;),with a list append as well