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Javascript

Nipplemilk909
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Go to solution Solved by myselfolli,
15 hours ago, M.Yurizaki said:

numbers[0];

Well yes, obviously...

looking for a program that takes an input of numbers and returns the min and max value of the set. 

 

 

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create a javascript function called findMinMax. This function should take an array of numbers and return an array with two numbers which are the min and max values of the array that was passed in. Log the returned value to the console.Do NOT use the array sort method or any pre-written min and max javascript functions. You also do not need to write your own sort method to solve this problem unless you want too. It can be solved without sorting the array. 

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In what format are the numbers saved? In an array, I'd assume? This is pretty easy to code.

 

There's probably I library for that xD

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What do you mean by you're looking for a program? Are you a coder and are asking for a solution to this? Or do you not know any code and just want a program which achieves that? In which case I'd question why the title is Javascript.

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4 minutes ago, Alir said:

What do you mean by you're looking for a program? Are you a coder and are asking for a solution to this? Or do you not know any code and just want a program which achieves that? In which case I'd question why the title is Javascript.

i just want a program in java that can accomplish this 

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Just now, Nipplemilk909 said:

i just want a program in java that can accomplish this 

So not Javascript?

 

Javascript and Java are two different languages.

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Just now, Alir said:

So not Javascript?

 

Javascript and Java are two different languages.

javascript 

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Can I ask what this is for? If you were given this as an assignment as part of a coding course, you would learn more and best to try and accomplish this yourself - it's pretty easy if you have some experience. If you don't, take a free Javascript course online. If you have any specific coding questions, we could answer those. But we won't be of any actual help if we just do it for you. Not that I wouldn't want to answer the simple question and then feel like a boss. But your education is more important than our ego.

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My bad. I just noticed that was you who replied with your requirements for this post and not someone posting an answer.

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I haven't coded JS in months. Just for your effort in not posting a generic request for help, I have given you 'some code' below. DON'T LOOK AT IT IF YOU HAVEN'T EVEN ATTEMPTED THE TASK. I say that for your sake. You won't learn anything that way and it won't be of any benefit to you. If you're completing this task because you need experience with loops, this is a perfect opportunity for you to learn, without looking at the answer

 

https://jsfiddle.net/eq2wxosu/

 

I haven't tested to see if it works. I'll leave that up to you. I have intentionally made mistakes.

 

If you need a decent web development course, check this out:

https://www.udemy.com/the-complete-web-developer-course-2/

 

Udemy often puts their courses on sale at £10. This course is a bargain at that price. You get free website hosting for a year - costs over £100 if you were to pay for it

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And no. I'm not making commission off that link or anything. That course is just actually good!

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function findMinMax(numbers){
  var min = numbers[0];
  var max = numbers[0];
  for (var i = 0; i < numbers.length; i++){
    if (numbers[i] > max){
      max = numbers[i];
    }
    if (numbers[i] < min){
      min = numbers[i];
    }
  }

  return [min, max];
}

There ya go

75% of what I say is sarcastic

 

So is the rest probably

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3 minutes ago, myselfolli said:

function findMinMax(numbers){
  var min = numbers[0];
  var max = numbers[0];
  for (var i = 0; i < numbers.length; i++){
    if (numbers[i] > max){
      max = numbers[i];
    }
    if (numbers[i] < min){
      min = numbers[i];
    }
  }

  return [min, max];
}

There ya go

 

y u du dis

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6 minutes ago, Alir said:

 

y u du dis

?

75% of what I say is sarcastic

 

So is the rest probably

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Just now, myselfolli said:

?

lol I was intentionally leaving mistakes so that he/she could debug and figure out the mistakes. Hence learning what was wrong and why. I naturally assumed this was a homework-style assignment so me posting the answer wouldn't have helped him/her learn.

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xD

 

Okay disregard my code, it apparently works too well :P

75% of what I say is sarcastic

 

So is the rest probably

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1 minute ago, myselfolli said:

xD

 

Okay disregard my code, it apparently works too well :P

Use jQuery. It great for quality bug-free code and does everythings

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Just now, Alir said:

Use jQuery. It great for quality bug-free code and does everythings

I know and usually I do, but it was (at least semi-clearly) stated, that we were supposed to use javascript.

75% of what I say is sarcastic

 

So is the rest probably

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In regards to the web dev course, if you're wondering how the guy makes money off of the web hosting if people are getting >£100 hosting for £10, 1) He makes long-term customers and 2) I assume most people end up not even taking advantage of it fully eg. giving up halfway through as is unfortunately the case with a lot of online courses that don't set you deadlines or give you a limited time to complete it in.

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Just now, myselfolli said:

I know and usually I do, but it was (at least semi-clearly) stated, that we were supposed to use javascript.

I meant

 

1 hour ago, Alir said:
Image result for javascript jquery joke

 

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9 hours ago, myselfolli said:

xD

is this how i would call it ?

function findMinMax(numbers){
  var min = numbers[0];
  var max = numbers[0];
  for (var i = 0; i < numbers.length; i++){
    if (numbers > max){
      max = numbers;
    }
    if (numbers < min){
      min = numbers;
    }
  }

  return [min, max];
}

findMinMax(3,2,2,4,6,7,78,9,3,21,6)

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2 hours ago, Nipplemilk909 said:

is this how i would call it ?

function findMinMax(numbers){
  var min = numbers[0];
  var max = numbers[0];
  for (var i = 0; i < numbers.length; i++){
    if (numbers > max){
      max = numbers;
    }
    if (numbers < min){
      min = numbers;
    }
  }

  return [min, max];
}

findMinMax(3,2,2,4,6,7,78,9,3,21,6)

You need to feed it an array.

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