Math Question (please help)
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Boomwebsearch
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in Off Topic
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Solved by 79wjd,
5 and 3
For future reference,
x+y=8 -> x=8-y
x*y=15 -> (8-y)y=15 ->8y-y^2-15=0 -> y=3,5
In this case it happens to work out that y has two solutions which are both correct, but it won't always work out that way, so then take both y's and see what x would be for each y.
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