Help with calculating leap year(java)

[yusup31]

   int x = -3 ;
      	Scanner scan = new Scanner(System.in); 
      			
 System.out.println("enter year that you want to know if it is a leap year( type -3 to quit): ");
  
 int y = scan.nextInt();
 while(y != x)
 	
 if(y >= 1582 )
 	{
 	 System.out.println("this year is not a leap year.");
 	}

Else if (y >= 1582 && (y%4==0 && y%100 == 0 && y%400 !=0 ))
 		{
 		 System.out.println("this year is a leap year.");	
	
		}
		else if (y>=1582 && (y%4==0 && y%100!=0))
	{System.out.println("this year is a leap year.");	
	}
		else (y <= 1582)
		 {
		 System.out.println("error Gregorian calendar not adopted until 1582");	
		 }
	
 	 

I am writing this program for my coding class and I cant seem to get my else if statements to be correct. When compiling the code it says that the last else has no if. any help is appreciated 

[Pinguinsan]

else cannot have a condition following it (y <= 1582). Remove this line and the program will be syntactically valid. I did not check the programs logic, but that is why it will not run as-is.

[fizzlesticks]

13 minutes ago, Erik Sieghart said:

Why would he put in a condition if he didn't want the code to execute on that condition?

Because that condition doesn't make sense (nor do the other 2 else ifs.)  If y isn't >= 1582 (failing the first if) than the last else if is always true which makes the condition meaningless.