Python how can I allow a function to accept a blank argument?

[Guest]

import turtle as tdef draw_space(x):    t.seth(360)    t.penup()    if x == '':        t.forward(50)        t.pendown()    else:        t.forward(x)        t.pendown()

This is using the turtle module just for an example here, but when I call the function such as so:

draw_space()

I want it to default to going forward by 50. However, If I run this, I get the error

TypeError: draw_space() missing 1 required positional argument: 'x'

But then if the parameter isn't left blank I want it to go forward, x. Ideas?

[Sauron]

you wrote x == ' ' instead of x == '\0'

[Guest]

you wrote x == ' ' instead of x == '\0'

def draw_space(x):    t.seth(360)    t.penup()    if x == '\0':        t.forward(50)        t.pendown()    else:        t.forward(x)        t.pendown()

Does the same thing

[babadoctor]

def draw_space(x):    t.seth(360)    t.penup()    if x == '\0':        t.forward(50)        t.pendown()    else:        t.forward(x)        t.pendown()

Does the same thing

 

use null parameter

[Guest]

use null parameter

Somehow I never learned how to do this, got any articles or references?

[Sauron]

def draw_space(x):    t.seth(360)    t.penup()    if x == '\0':        t.forward(50)        t.pendown()    else:        t.forward(x)        t.pendown()

Does the same thing

 

 

try "if !x"

[Guest]

try "if !x"

Just says invalid syntax for me, I'm doing something wrong.

[Guest]

Got it

def draw_space(x=50):    t.seth(360)    t.penup()    if x is None:        t.forward(50)        t.pendown()    else:        t.forward(x)        t.pendown()

[Sauron]

Just says invalid syntax for me, I'm doing something wrong.

 

sorry, I misread the question what you're doing wrong is very simple: you aren't passing any argument on to the function. You can't call draw_space() without passing it the "x" argument. calling draw_space(' ') with the original code should do the trick.