Need Help with Maths...

[werto165]

 

This is what I've got so far: 

I'm pretty sure I'm doing something wrong, any help would be appreciated. I think It's meant to be the chain rule but I can't seem to get the right answer. 

[mansoor_]

you forgot the product rule on the first term. 

 

 

 

 

 

 

 

 

 

ANS:

2x(2+y) + x^2 dy/dx - 2y dy/dx = 0

then rearrange for an expression equal to dy/dx.

 

dy/dx = (2x(2+y)) / (2y - x^2)

[Kyuubixchidori]

eek. glad im taking econ. and i love how theres 9 users looking at a math question lol. this fourm is great. 

[werto165]

you forgot the product rule on the first term. 

 

 

 

 

 

 

 

 

 

ANS:

2x(2+y) + x^2 dy/dx - 2y dy/dx = 0

then rearrange for an expression equal to dy/dx.

Jesus I feel so retarded right now... 

[Kyuubixchidori]

Jesus I feel so retarded right now... 

dude its fine, id of made the same mistake 

[Epic_Nex]

hold on...

[Epic_Nex]

i got the answer as  (-2xy - 4x)/(2y - x^2)

[TwoFace1090]

@Epic_Nex   Me too!

[TwoFace1090]

resp. my solution is (2xy+4x)/(x²-2y), which is just the same times (-1)