Help in C++

[alphabeta]

The output is right but it says wrong in Code Forces  

#include <iostream>#include<math.h>using namespace std;int main(){int h1,min1,h2,min2;cin>>h1>>min1>>h2>>min2;if(h1==h2)    cout<<(24*60)-fabs(min1-min2);    else if (h1>h2)        cout<<((fabs((h1-24)+fabs(h2%12))*60))-fabs(min1-min2);    else if (h2>h1)        cout<<((h2-h1)*60)-fabs(min1-min2);}

[espurritado]

well, first of all, h1 will never be higher than h2, so you can get rid of that case, second, you don't need the math library, if h1==h2 then the answer would be m2-m1 and if h2>h1 the answer would be (h2-h1)*60+(m2-m1)

#include <iostream>using namespace std;void main(){int h1, m1, h2, m2;cin>>h1>>m1>>h2>>m2;cout<<(h2-h1)*60+(m2-m1);}

you can use this if you are too lazy to even use if clauses

this is assuming the go to bed and wake up time occur during the same day

[alphabeta]

well, first of all, h1 will never be higher than h2, so you can get rid of that case, second, you don't need the math library, if h1==h2 then the answer would be m2-m1 and if h2>h1 the answer would be (h2-h1)*60+(m2-m1)

#include <iostream>using namespace std;void main(){int h1, m1, h2, m2;cin>>h1>>m1>>h2>>m2;cout<<(h2-h1)*60+(m2-m1);}

you can use this if you are too lazy to even use if clauses

this is assuming the go to bed and wake up time occur during the same day

 

I thought about h1>h2 'cause it's 24-Hour format so h1 might be (22) and h2 (5) for example