More networking questions

[ladybug]

Hey,can you help me with a network question I have?

I did my best to translate it

What network mask must be placed in order for a network with address 192.168.99.0 to be divided    into at least 4 subnets? 
What are the new subnets, gateways, and destination IP addresses?

[Lurick]

Look at subnet masks from /25 to /32 and see which one gives you enough to divide a /24 (256) evenly into 4 subnets first.

Subnet= 192.168.99.x/yy

Gateway= 192.168.99.x(of subnet address) + 1

Broadcast= 192.168.99.x(of next subnet address) minus 1

 

Example: Divided into two /25 subnets, the first would be

Subnet= 192.168.99.0/25

Gateway= 192.168.99.1

Broadcast= 192.168.99.127 (since the next subnet is 192.168.99.128/25)

 

Edit:

Fixed my typos

[ladybug]

17 minutes ago, Lurick said:

Look at subnet masks from /25 to /32 and see which one gives you enough to divide a /24 (256) evenly into 4 subnets first.

Subnet= 192.168.99.x/yy

Gateway= 192.168.99.x(of subnet address) + 1

Broadcast= 192.168.99.x(of next subnet address) minus 1

 

Example: Divided into two /25 subnets, the first would be

Subnet= 192.168.99.0/25

Gateway= 192.168.99.1

Broadcast= 192.168.99.125 (since the next subnet is 192.168.99.126/25)

ok I just don't get how the broadcast is formed(why is the next subnet 126) the other things I think I got

[Allan B]

Because he is off by a few numbers.

 

192.168.99.0/25 would be 192.168.99.1-126 with broadcast being 127.

192.168.99.128/25 would be 192.168.99.129-254 with broadcast being 255.

 

Into 4 subnets you would use /26 with the 4 networks below.  The network "ID" (0/64/128/192) ip you cannot use, also the broadcast IPs (63/127/191/255)

192.168.99.0/26 - 192.168.99.1-62 (Broadcast 63) 

192.168.99.64/26 - 192.168.99.65-126 (127)

192.168.99.128/26 - 192.168.99.129-190 (191)

192.168.99.192/26 - 192.168.99.193-254 (255)

 

"/26" means the subnet mask is 255.255.255.192.

The "gateway" is whatever ip you set the firewall\router to be within each range.. (it does not have to be .1 for example)

[Lurick]

28 minutes ago, Allan B said:

Because he is off by a few numbers.

 

192.168.99.0/25 would be 192.168.99.1-126 with broadcast being 127.

192.168.99.128/25 would be 192.168.99.129-254 with broadcast being 255.

 

Into 4 subnets you would use /26 with the 4 networks below.  The network "ID" (0/64/128/192) ip you cannot use, also the broadcast IPs (63/127/191/255)

192.168.99.0/26 - 192.168.99.1-62 (Broadcast 63) 

192.168.99.64/26 - 192.168.99.65-126 (127)

192.168.99.128/26 - 192.168.99.129-190 (191)

192.168.99.192/26 - 192.168.99.193-254 (255)

 

"/26" means the subnet mask is 255.255.255.192.

Doh, good catch, I was thinking about 26 since that is the answer (/26s) but not wanting to give it away without having OP do a little research.

[ladybug]

39 minutes ago, Allan B said:

Because he is off by a few numbers.

 

192.168.99.0/25 would be 192.168.99.1-126 with broadcast being 127.

192.168.99.128/25 would be 192.168.99.129-254 with broadcast being 255.

 

Into 4 subnets you would use /26 with the 4 networks below.  The network "ID" (0/64/128/192) ip you cannot use, also the broadcast IPs (63/127/191/255)

192.168.99.0/26 - 192.168.99.1-62 (Broadcast 63) 

192.168.99.64/26 - 192.168.99.65-126 (127)

192.168.99.128/26 - 192.168.99.129-190 (191)

192.168.99.192/26 - 192.168.99.193-254 (255)

 

"/26" means the subnet mask is 255.255.255.192.

Ok thanks!