IF not picking up the correct condition -JAVA-

[Igor Perrotta]

Hey everyone, how are you guys today? 

I'm doing a round robin scheduler and i've come across this problem.

The tempodeExecucao variable is in the correct amount and so does the cpu[0].vetordeIO as the screenshot shows. but it won't go into the if.

i need the verification to work so i can send the process on the queue.

thanks for the help!

if (cpu[0].vetorDeIO.length != 0) {
                    if (cpu[0].tempodeExecucao == cpu[0].vetorDeIO) {
                        System.out.println("OPERACAO IO");
                        System.out.println("NOME E TEMPO DE EXECUCAO " + cpu[0].getNome() + cpu[0].tempodeExecucao);
                        filaexecucao.enqueueProcess(cpu[0]);
                        cpu[0] = filaexecucao.dequeueProcess();
                    
                        break;

                    }
                }

[reniat]

i'm a bit confused as to whats going on here, since it looks like vetorDelO is some kind of collection based on the variable view there, but you are directly comparing it to the temposeExecucao, which looks like a numeric primitive, which shouldn't compile. More context in the code would help here.

[Timotheus2]

It seems like you forgot to access the 0th element of vetorDeIO, but that should usually give an error or warning.

[AnotherMax]

Second "if" statement, the `cpu[0].vetorDeIO` looks to be an array.

// cpu[0].vetorDeIO  => cpu[0].vetorDeIO[0]
// this
if (cpu[0].tempodeExecucao == cpu[0].vetorDeIO) {...
// to
if (cpu[0].tempodeExecucao == cpu[0].vetorDeIO[0]) {...
  

 

[Igor Perrotta]

Thanks for the replies guys, sorry for explaining badly what was going on, I was in a rush. but I was able to solve it, I was comparing a char with an int. I used Character.getNumericValue and the if was able to verify correctly!