C++ splitting string into array.

[rans]

Can anyone help me? i wanted to split a user input strings into array. seperating them by "," (comma) and will ignore curly braces and spaces. the user must input {abc,def,ghi} (including the curly braces).
the result should be like:
 

array[0] = abc
array[1] = def
array[2] = ghi

 

i'm so lost and really confuse splitting string.
here is my code

#include <sstream>
#include "iostream"
using namespace std;

int main(){
    string line;
    cin >> line;
    string arr[4];
    int i = 0;
    stringstream ssin(line);
    while (ssin.good() && i < 4){
        ssin >> arr[i];
        ++i;
    }
    for(i = 0; i < 4; i++){
        cout << arr[i] << endl;
    }
}

 

[LtStaffel]

I'd be using (the probably extremely inefficient solution) of strcmp, keeping track of the location of the last comma and then when I find another I'd add that string in between to the array.

[Unimportant]

51 minutes ago, Ranz said:

<snip>

One would probably want to use regex for this, which has been added to the C++ 11 standard. For a normal solution, maybe something along these lines?

#include <iostream>
#include <string>
#include <sstream>
#include <vector>

int main() 
{
	/* Read input string from user */
	std::string input;
	if (!std::getline(std::cin, input))
	{
		std::cout << "Failed to read input string!\n";
		return 1;
	}

	/* find position of open brace { and closing brace }...
	   display error message if one or both braces not found... */	
	auto openBracePos = input.find('{');
	auto closeBracePos = input.find('}');
	if (openBracePos == std::string::npos
	||  closeBracePos == std::string::npos)
	{
		std::cout << "Input string format error, {} braces not found!\n";
		return 2;
	}
	
	/* Create a stringstream from the substring between the braces {} */
	std::stringstream instream(input.substr(openBracePos + 1, closeBracePos - openBracePos - 1));

	/* Create the vector to store the result. */
	std::vector<std::string> arr;

	/* Use getline to get each substring using ',' as delimiter. */
	std::string s;
	while (std::getline(instream, s, ','))
	{
		s.erase(0, s.find_first_not_of(' '));   //remove leading spaces
		arr.push_back(s);
	}

	/* Print result. */
	std::cout << arr.size() << " strings read.\n";
	for (const auto& s : arr)
	{
		std::cout << s << '\n';
	}


	return 0;
}

 

[rans]

38 minutes ago, Unimportant said:

One would probably want to use regex for this, which has been added to the C++ 11 standard. For a normal solution, maybe something along these lines?

#include <iostream>
#include <string>
#include <sstream>
#include <vector>

int main() 
{
	/* Read input string from user */
	std::string input;
	if (!std::getline(std::cin, input))
	{
		std::cout << "Failed to read input string!\n";
		return 1;
	}

	/* find position of open brace { and closing brace }...
	   display error message if one or both braces not found... */	
	auto openBracePos = input.find('{');
	auto closeBracePos = input.find('}');
	if (openBracePos == std::string::npos
	||  closeBracePos == std::string::npos)
	{
		std::cout << "Input string format error, {} braces not found!\n";
		return 2;
	}
	
	/* Create a stringstream from the substring between the braces {} */
	std::stringstream instream(input.substr(openBracePos + 1, closeBracePos - openBracePos - 1));

	/* Create the vector to store the result. */
	std::vector<std::string> arr;

	/* Use getline to get each substring using ',' as delimiter. */
	std::string s;
	while (std::getline(instream, s, ','))
	{
		s.erase(0, s.find_first_not_of(' '));   //remove leading spaces
		arr.push_back(s);
	}

	/* Print result. */
	std::cout << arr.size() << " strings read.\n";
	for (const auto& s : arr)
	{
		std::cout << s << '\n';
	}


	return 0;
}

 

Thank you very much! such an effort ty