C++ Count digits in double

[Guest]

Google has failed me again.

 

I have a program that displays data in the form of doubles, however if the double has more than 5 or so digits I want to trim it down to be only 5 digits

Something like this:

int length_var;double var = 43.4556;int cutoff = 5;length_var = var.len(); // <-- no ideafor (var_length >= cutoff) {	remove_last(length_var) // <-- no idea again}

So... I need to find out the number of digits in a double and then figure out how to remove the last digit

[Nineshadow]

All digits in total?

Or just the ones after '.' ?

[Enderman]

have you already read these or am I just better at googling things than you?

http://stackoverflow.com/questions/798046/digit-limitation-from-decimal-point-in-c

http://stackoverflow.com/questions/3383817/limit-floating-point-precision

[Guest]

All digits in total?

Or just the ones after '.' ?

All of them.

[Nineshadow]

All of them.

So, for 1.547 , the length would be 4. For 12345.6789 , the length would be 9. For 1234.0 the length would be 4 or 5?

 

Or do you just want to write the doubles only with the first 5 digits?

[Guest]

have you already read these or am I just better at googling things than you?

http://stackoverflow.com/questions/798046/digit-limitation-from-decimal-point-in-c

http://stackoverflow.com/questions/3383817/limit-floating-point-precision

You have stronger google-fu but I'm hoping theres an easier and cleaner solution

[Guest]

So, for 1.547 , the length would be 4. For 12345.6789 , the length would be 9. For 1234.0 the length would be 4 or 5?

 

Or do you just want to write the doubles only with the first 5 digits?

I want to remove the last few digits

And yes, that's correct 53.1245 would be length of 6