c++ backward integer

[WildCAt]

Hello! ^^

 

I am writing a program and I need to reverse my integer number to continue

For example, I have

 

int num_b; 

int num=123;

 

and I need   num_b   to be 321

 

I've been searching on the web, but found only int-string solutions or print numbers on screen step-by-step;

 

I do not need to print the number, I need to have my number to be int and reversed to continue calculations.

 

Can you help me?

And sorry for my English ^^"""

[Nineshadow]

@WildCAt It's pretty simple.

int rev(int n){    int x = 0;    while(n)    {        x = x * 10 + n%10;        n/=10;    }    return x;}

Do you understand how it works?

You initialize your new backward number to 0. Then, you make your new number itself times 10 (to make place for another digit) , then add the last digit of the original number. Then you divide your original number by 10 to get to the next digit and you keep going on until the original number becomes 0.

[WildCAt]

@WildCAt It's pretty simple.

int rev(int n){    int x = 0;    while(n)    {        x = x * 10 + n%10;        n/=10;    }    return x;}

Do you understand how it works?

You initialize your new backward number to 0. Then, you make your new number itself times 10 (to make place for another digit) , then add the last digit of the original number. Then you divide your original number by 10 to get to the next digit and you keep going on until the original number becomes 0.

 

Thanks!! ^_________^

Yeah, really simple)