How do i return a double floating value?

[airfrog19]

Can someone show me an example of this?

[madknight3]

I donno...like this?

public double Example() {    double d = 1.1;    return d;    // could also shorten to    // return 1.1;}

What language are you using?

[airfrog19]

I donno...like this?

public double Example() {    double d = 1.1;    return d;    // could also shorten to    // return 1.1;}

What language are you using?

i'm using java. like what if it's public double toDouble?

[madknight3]

i'm using java. like what if it's public double toDouble?

 

Sorry, you're going to have to give me a little more to work with. Try to explain more about what you're trying to do. Show some code if you can as that may also help.

[airfrog19]

Sorry, you're going to have to give me a little more to work with. Try to explain more about what you're trying to do. Show some code if you can as that may also help.

i don't really have any code, but i'm building a fraction class and it has to return a double floating point value

[madknight3]

i don't really have any code, but i'm building a fraction class and it has to return a double floating point value

 

Ok, well if it's a simple fractions class then I'll assume both the numerator and denominator are integers.

 

So in your function you should just be able to do

return (double) numerator/denominator;

The "(double)" part will cast the numerator to the double type. When division happens between a double and an int, it's result will be a double.

// This prints 0 because it's integer division (cuts the result off at the decimal place)System.out.println( 1/2 );// All these print 0.5 because it does floating point division when one or both numbers are a doubleSystem.out.println( 1.0/2 );System.out.println( 1/2.0 );System.out.println( 1.0/2.0 );System.out.println( (double)1/2 );System.out.println( 1/(double)2 );

Note that the cast happens before the division. So

// This casts 1 to a double before dividing by two which results in 0.5(double) 1 / 2// This does the division first resulting in zero, then casts that result of zero to a double. So 0.0(double) (1 / 2)

[airfrog19]

[madknight3]

 

like put return (double) numerator/denominator in 

public double toDouble{}

 

Yeah the function would look something like

public double toDouble() {    return (double) numerator/denominator;}

Assuming that the numerator and denominator are fields in your class. If not, you'd have to pass them in as parameters

public double toDouble(int numerator, int denominator) {    return (double) numerator/denominator;}

Note that you should also handle the "division by zero" error that can occur.